**Chemical Reaction Rate Analysis**Please describe what would happen to the rate if given changes were applied to the following reactions:**Example:***Doubling the concentration of both KOH and starting material in the reaction below*\[ \text{Br}\text{-alkane} + \text{KOH (in DMF)} \rightarrow \text{OH-alkane} \]- **Explanation**: It is a 2nd order reaction. Doubling the concentration of both reactants will result in 4x the speed of the reaction.---1. **Doubling the concentration of starting material and alcohol in the reaction below** \[ \text{Br}\text{-alkane} + \text{CH}_3\text{OH} \rightarrow \text{OCH}_3\text{-alkane} \] - **Reaction Diagram Explanation**: The reaction involves a Br-alkane reacting with methanol (CH₃OH) to produce an OCH₃-substituted alkane.2. **Using half of the alcohol in the reaction shown below** \[ \text{Br}\text{-alkane} + \text{CH}_3\text{OK + CH}_3\text{OH} \rightarrow \text{Alkene} \] - **Reaction Diagram Explanation**: Here, the reaction shows a Br-alkane reacting with CH₃OK in the presence of an excess of methanol (CH₃OH) to produce an alkene, indicating a possible elimination reaction. Reducing the alcohol amount might slow down the reaction rate depending on its role as a solvent or participant.

In the reaction 1 . The reaction goes via sN2 mechanism in the single step. Reaction 2. This…

Ex.: Doubling the concentration of both KOH and starting material in the reaction below Br OH KOH It is a 2nd order reaction. Doubling the concentration of both will result in 4x the speed of the reaction. DMF 1. Doubling the concentration of starting material and alcohol in the reaction below I Br Br CH₂OH 2. Using half of the alcohol in the reaction shown below CH,OK CH3OH

Ex.: Doubling the concentration of both KOH and starting material in the reaction below Br OH KOH It is a 2nd order reaction. Doubling the concentration of both will result in 4x the speed of the reaction. DMF 1. Doubling the concentration of starting material and alcohol in the reaction below I Br Br CH₂OH 2. Using half of the alcohol in the reaction shown below CH,OK CH3OH

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

**Chemical Reaction Rate Analysis**

Please describe what would happen to the rate if given changes were applied to the following reactions:

**Example:**

*Doubling the concentration of both KOH and starting material in the reaction below*

\[ \text{Br}\text{-alkane} + \text{KOH (in DMF)} \rightarrow \text{OH-alkane} \]

- **Explanation**: It is a 2nd order reaction. Doubling the concentration of both reactants will result in 4x the speed of the reaction.

---

1. **Doubling the concentration of starting material and alcohol in the reaction below**

\[ \text{Br}\text{-alkane} + \text{CH}_3\text{OH} \rightarrow \text{OCH}_3\text{-alkane} \]

- **Reaction Diagram Explanation**: The reaction involves a Br-alkane reacting with methanol (CH₃OH) to produce an OCH₃-substituted alkane.

2. **Using half of the alcohol in the reaction shown below**

\[ \text{Br}\text{-alkane} + \text{CH}_3\text{OK + CH}_3\text{OH} \rightarrow \text{Alkene} \]

- **Reaction Diagram Explanation**: Here, the reaction shows a Br-alkane reacting with CH₃OK in the presence of an excess of methanol (CH₃OH) to produce an alkene, indicating a possible elimination reaction. Reducing the alcohol amount might slow down the reaction rate depending on its role as a solvent or participant.

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