Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![Consider the reaction
2X2Y+ Z2 = 2X2YZ
which has a rate law of
rate = k[X2 Y][Z2]
Select a possible mechanism for the reaction.
• View Available Hint(s)
Step 1: Z2→Z+Z
Step 2: X2Y +Z→X2YZ (fast)
Step 3:
(slow)
А
X2Y+Z→X2YZ (fast)
Step 1: X2Y+Z2→X2YZ+Z (slow)
X2Y+Z→X2YZ (fast)
Step 2:
Step 1: X2Y +Z2→X2YZ2 (slow)
C
Step 2: X2YZ2→X2YZ+Z (fast)
Step 1: 2X2Y =X4Y2 (fast)
Step 2: X4Y2 +Z2→2X2YZ (slow)
OD
E
Step 1: 2X2Y+Z2→2X2YZ (slow)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c6de790-3967-4822-b83d-f877aa472903%2Fd21b313f-9beb-4328-a9f8-011d58aef94f%2Fl6nio5o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the reaction
2X2Y+ Z2 = 2X2YZ
which has a rate law of
rate = k[X2 Y][Z2]
Select a possible mechanism for the reaction.
• View Available Hint(s)
Step 1: Z2→Z+Z
Step 2: X2Y +Z→X2YZ (fast)
Step 3:
(slow)
А
X2Y+Z→X2YZ (fast)
Step 1: X2Y+Z2→X2YZ+Z (slow)
X2Y+Z→X2YZ (fast)
Step 2:
Step 1: X2Y +Z2→X2YZ2 (slow)
C
Step 2: X2YZ2→X2YZ+Z (fast)
Step 1: 2X2Y =X4Y2 (fast)
Step 2: X4Y2 +Z2→2X2YZ (slow)
OD
E
Step 1: 2X2Y+Z2→2X2YZ (slow)
Expert Solution

Step 1
The reaction is, 2X2Y + Z2 <=>2X2YZ.
Rate law of this reaction,
Rate = K[X2Y ][Z2 ]
Step by step
Solved in 2 steps

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