Consider the reaction2X2Y+ Z2 = 2X2YZwhich has a rate law ofrate = k[X2 Y][Z2]Select a possible mechanism for the reaction.• View Available Hint(s)Step 1: Z2→Z+ZStep 2: X2Y +Z→X2YZ (fast)Step 3:(slow)АX2Y+Z→X2YZ (fast)Step 1: X2Y+Z2→X2YZ+Z (slow)X2Y+Z→X2YZ (fast)Step 2:Step 1: X2Y +Z2→X2YZ2 (slow)CStep 2: X2YZ2→X2YZ+Z (fast)Step 1: 2X2Y =X4Y2 (fast)Step 2: X4Y2 +Z2→2X2YZ (slow)ODEStep 1: 2X2Y+Z2→2X2YZ (slow)

The reaction is, 2X2Y + Z2 <=>2X2YZ. Rate law of this reaction, Rate = K[X2Y ][Z2 ]

Answered: Step 1: X2Y+Z2→X2YZ+ Z (slow) B

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Step 1: X2Y+Z2→X2YZ+ Z (slow) B

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Consider the reaction
2X2Y+ Z2 = 2X2YZ
which has a rate law of
rate = k[X2 Y][Z2]
Select a possible mechanism for the reaction.
• View Available Hint(s)
Step 1: Z2→Z+Z
Step 2: X2Y +Z→X2YZ (fast)
Step 3:
(slow)
А
X2Y+Z→X2YZ (fast)
Step 1: X2Y+Z2→X2YZ+Z (slow)
X2Y+Z→X2YZ (fast)
Step 2:
Step 1: X2Y +Z2→X2YZ2 (slow)
C
Step 2: X2YZ2→X2YZ+Z (fast)
Step 1: 2X2Y =X4Y2 (fast)
Step 2: X4Y2 +Z2→2X2YZ (slow)
OD
E
Step 1: 2X2Y+Z2→2X2YZ (slow)

Expert Solution

Step 1

The reaction is, 2X₂Y + Z₂<=>2X₂YZ.

Rate law of this reaction,

Rate = K[X₂Y ][Z₂]

Step by step

Solved in 2 steps

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