Gaseous hydrochloric acid is produced from molecular hydrogen and molecular chlorine according to the following three-step mechanism at 20 °C. The enthalpy energetic is based on 0.17 mol starting material. Remember as a rule of thumb that for every 10° increase in temperature, the reaction rate doubles. (Show complete work for full credit) Step 1: (fast) Cl2 (g) 2C1 (g) Et = 80 kJ AH1 = 50 kJ Eacti = 60 kJ Step 2: (fast) H2 (g) Cl (g) = H2CI (g) Ez* = 90 kJ AH2 = -25kJ E act1 kJ +] Step 3: (slow) H2CI (9) • Cl (g) → 2HCI (9) E, = 110kJ AH3 = _ kJ EHCI =- 10 kJ Write the net reaction. What is/are the intermediate(s) for this reaction? What is the catalyst? a. Net Rxn: Intermediates: Catalyst: b. What is the rate constant for this reaction at 20.00 °C? Include the value of K and the units. Use A = 5,550-107 M s!

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter13: Chemical Kinetics
Section: Chapter Questions
Problem 13.72QE
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Gaseous hydrochloric acid is produced from molecular hydrogen and molecular chlorine according to the following three-step
mechanism at 20 °C. The enthalpy energetic is based on 0.17 mol starting material. Remember as a rule of thumb that for
every 10° increase in temperature, the reaction rate doubles. (Show complete work for full credit)
Step 1: (fast)
Cl2 (g) = 2C1 (g)
Ef = 80 kJ
AH, = 50 kJ
E- 60 kJ
act1
Step 2: (fast)
H2 (g)
CI (9) = H2CI (9)
Ez* = 90 kJ
AH2 = -25kJ
kJ
act1
Step 3: (slow)
H2CI (g)
CI (g)
E, = 110kJ
→2HCI
(g)
AH3 =
_ kJ
EHa = - 10 kJ
Write the net reaction. What is/are the intermediate(s) for this reaction? What is the catalyst?
Net Rxn:
a.
Intermediates:
Catalyst:
b,
What is the rate constant for this reaction at 20.00 °C? Include the value of K and the units. Use A = 5.550-107 Mst.
Transcribed Image Text:Gaseous hydrochloric acid is produced from molecular hydrogen and molecular chlorine according to the following three-step mechanism at 20 °C. The enthalpy energetic is based on 0.17 mol starting material. Remember as a rule of thumb that for every 10° increase in temperature, the reaction rate doubles. (Show complete work for full credit) Step 1: (fast) Cl2 (g) = 2C1 (g) Ef = 80 kJ AH, = 50 kJ E- 60 kJ act1 Step 2: (fast) H2 (g) CI (9) = H2CI (9) Ez* = 90 kJ AH2 = -25kJ kJ act1 Step 3: (slow) H2CI (g) CI (g) E, = 110kJ →2HCI (g) AH3 = _ kJ EHa = - 10 kJ Write the net reaction. What is/are the intermediate(s) for this reaction? What is the catalyst? Net Rxn: a. Intermediates: Catalyst: b, What is the rate constant for this reaction at 20.00 °C? Include the value of K and the units. Use A = 5.550-107 Mst.
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