Derive the rate law for the following reaction given the mechanistic steps below: 2NO(g) + O₂(g) 2NO₂(g), rate= e=k [NO]²[0₂] The mechanism proposed for this reaction consists of two steps. The first step is a fast equilibrium. k₁ 2 NO(g) k_1 - rate= N₂O₂(g) k₂ N₂0₂ (8) + O₂(g) → 2NO₂ (g) What is the rate law in terms of k₁, k₂, and k_₁? Be sure to simplify the rate law before inputting your answer. [NO]²[0₂] 00 00

Chemistry: Matter and Change
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Chapter16: Reaction Rates
Section: Chapter Questions
Problem 70A
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Derive the rate law for the following reaction given the mechanistic steps below:
2NO₂(g), rate=k[NO]²[0₂]
The mechanism proposed for this reaction consists of two steps. The first step is a fast equilibrium.
k₁
2NO(g) + O₂(g) → 2NO₂(g), rate= k
2 NO(g)
k_
1
rate=
N₂O₂(g)
k₂
N₂O₂(g) + O₂(g) →→→ 2NO₂ (g)
What is the rate law in terms of k₁, k₂, and k_₁? Be sure to simplify the rate law before inputting your answer.
[NO]²[0₂]
00
X
Ś
0|0
Transcribed Image Text:Derive the rate law for the following reaction given the mechanistic steps below: 2NO₂(g), rate=k[NO]²[0₂] The mechanism proposed for this reaction consists of two steps. The first step is a fast equilibrium. k₁ 2NO(g) + O₂(g) → 2NO₂(g), rate= k 2 NO(g) k_ 1 rate= N₂O₂(g) k₂ N₂O₂(g) + O₂(g) →→→ 2NO₂ (g) What is the rate law in terms of k₁, k₂, and k_₁? Be sure to simplify the rate law before inputting your answer. [NO]²[0₂] 00 X Ś 0|0
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