-313(C) Based on your answer to part (b), choose what can be concluded, at the 0.10 level of significance, about the claim made by the expert.O Since the value of the test statistic lies in the rejection region, the null hypothesis is rejected. So, there isenough evidence to support the claim that the mean amount of gamma radiation needed to sterilize a colony oftardigrades is not equal to 1000 Gy.O Since the value of the test statistic lies in the rejection region, the null hypothesis is not rejected. So, there isnot enough evidence to support the claim that the mean amount of gamma radiation needed to sterilize acolony of tardigrades is not equal to 1000 Gy.O Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is rejected. So, there isenough evidence to support the claim that the mean amount of gamma radiation needed to sterilize a colony oftardigrades is not equal to 1000 Gy.Since the value of the test statistic doesn't lie in the rejection region, the null hypothesis is not rejected. So,there is not enough evidence to support the claim that the mean amount of gamma radiation needed to sterilize Tardigrades, or water bears, are a type of micro-animal famous for their resilience. In examining the effects of radiation on organisms, an expert claimed thatthe amount of gamma radiation needed to sterilize a colony of tardigrades no longer has a mean of 1000 Gy (grays). (For comparison, humans cannotEspewithstand more than 10 Gy.) A random sample of 25 tardigrade colonies found that the amount of gamma radiation needed to sterilize a colony had a samplemean of 965 Gy, with a sample standard deviation of 60 Gy. Assume that the population of amounts of gamma radiation needed to sterilize a colony oftardigrades is approximately normally distributed.Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level of significance, to support that u, the mean amountof gamma radiation needed to sterilize a colony of tardigrades, is not equal to 1000 Gy.(a) State the null hypothesis H, and the alternative hypothesis H, that you would use for the test.Ho:(b) Perform a hypothesis test. The test statistic has a t distribution (so the test is a "t test"). Here is some other information to help you with your test.In o5 is the value that cuts off an area of 0.05 in the right tail.fo.05O The value of the test statistic is aiven bv t =

We have to perform two tailed t test for the mean.

Answered: Tardigrades, or water bears, are a type…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The null hypothesis: H. :|| The alternative hypothesis: H :0 1 The type of test statistic: (Choose one) v The value of the test statistic: (Round to at least three decimal places.) The p-value: (Round to at least three decimal places.) Can we reject the researchers' claim that the mean recovery time when treated with multivitamin is less than or equal to the mean recovery time when treated with vitamin C only? Yes No
Captivity can influence immunological responses in some mammals. Seeber et al. (2020) investigated various aspects of immunological responses in captive and free-ranging zebras. One aspect of the study involved samples of 12 free-ranging zebras from Namibia, 9 from Tanzania, and 38 captive zebras from various zoos in Europe. (All of these were non-lactating females.) One of the measured variables from blood samples was lysozyme concentration (μg/L). (Lysozyme is a biomarker of the immune response.) The researchers were interested in investigating possible differences in lysozyme concentration between zebras in the various locations. As part of the analysis, they carried out a one-way ANOVA on the lysozyme concentrations for the zebras from the 3 locations, and found the following output. Df Sum Sq Mean Sq F value Pr(>F) Location 2 50.65 25.33 42.24 6.54e-12Residuals 56 33.57 0.60 Suppose the assumptions of one-way ANOVA…
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Inorganic phosphorous is a naturally occurring element in all plants and animals, with concentrations increasing progressively up the food chain (fruit < vegetables < cereals < nuts < corpse). Geochemical surveys take soil samples to determine phosphorous content (in ppm, parts per million). A high phosphorous content may or may not indicate an ancient burial site, food storage site, or even a garbage dump. Independent random samples from two regions gave the following phosphorous measurements (in ppm). Assume the distribution of phosphorous is mound-shaped and symmetric for these two regions. Region I: x,; n, = 15 875 1,080 2,330 1,850 1,860 853 1,551 1,230 2,340 1,080 910 1,130 1,450 1,260 1,010 Region II: x,; n, = 14 540 808 790 1,230 1,770 960 1,650 860 890 640 1,180 1,160 1,050 | 1,020 In USE SALT (a) Use a calculator with mean and standard deviation keys to verify that x,, S,, x2, and s,. (Round your answers to four decimal places.) X1 ppm S. = ppm X2 ppm 52 ppm (b) Let u, be the…
Srddh
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You are concerned that nausea may be a side effect of Tamiflu, but you cannot just give Tamiflu to patients with the flu and say that nausea is a side effect if people become nauseous. This is because nausea is common for people who have the flu. From past studies you know that about 34% of people who get the flu experience nausea. You collected data on 1926 patients who were taking Tamiflu to relieve symtoms of the flu, and found that 711 experienced nausea. Use a 0.01 significance level to test the claim that the percentage of people who take Tamiflu for the relief of flu symtoms and experience nausea is greater than 34%. a) Identify the null and alternative hypotheses? Ho: ? H₁: ? b) What type of hypothesis test should you conduct (left-, right-, or two-tailed)? left-tailed right-tailed O two-tailed c) Identify the appropriate significance level. d) Calculate your test statistic. Write the result below, and be sure to round your final answer to two decimal places. e) Calculate your…
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