Table 1 Test results Sample 1 2 3 W (mm) B (mm) a (mm) Load at failure (kN) 20 5 9.8 2.3 20 10 9.4 4.4 20 2 2 2 20 20 10.1 8.6 For the geometry used, the stress at failure is calculated from 225P B Pa where P is in newtons and B is in metres. (Note that this is an empirical formula so the units do not balance.) i. Use the 'Beam in pure bending - through-thickness edge crack' geometry in the K- calculator to calculate the value of K at failure for the three samples. (10 marks) ii. In order for a valid fracture toughness value to be obtained, both the sample thickness B and the final crack length a should satisfy B, a 2.5 KQ σyield 2 where KQ is the estimated toughness value of K at failure, and σ yield is the yield strength of the material. In this case σ yield = 620 MPa. Calculate whether the samples are sufficiently thick (i.e. whether B is large enough) to meet this criterion. Are the final crack lengths acceptable? (10 marks) Beam in pure bending - through-thickness edge crack Calculate: KI Material properties: O Critical crack length O Critical stress ○ KIC KIC: 31.33 MPa Vm Geometry dimensions: Width (2W): 40.000 mm Crack length (2a): 0.100 mm Y: 1.00 Loading: Stress: 2500.00 MPa KI: 31.33 MPa Vm Reserve factor on the load: 1.00

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Please can you help me answer the question added in the images below. I have also attatched an image of the k calculator i have to use. 

Table 1 Test results
Sample
1
2
3
W (mm)
B (mm)
a (mm)
Load at failure (kN)
20
5
9.8
2.3
20
10
9.4
4.4
20
2 2 2
20
20
10.1
8.6
For the geometry used, the stress at failure is calculated from
225P
B
Pa
where P is in newtons and B is in metres. (Note that this is an empirical formula so the
units do not balance.)
i. Use the 'Beam in pure bending - through-thickness edge crack' geometry in the K-
calculator to calculate the value of K at failure for the three samples.
(10 marks)
ii. In order for a valid fracture toughness value to be obtained, both the sample
thickness B and the final crack length a should satisfy
B, a 2.5
KQ
σyield
2
where KQ is the estimated toughness value of K at failure, and σ yield is the yield
strength of the material. In this case σ yield = 620 MPa.
Calculate whether the samples are sufficiently thick (i.e. whether B is large
enough) to meet this criterion. Are the final crack lengths acceptable?
(10 marks)
Transcribed Image Text:Table 1 Test results Sample 1 2 3 W (mm) B (mm) a (mm) Load at failure (kN) 20 5 9.8 2.3 20 10 9.4 4.4 20 2 2 2 20 20 10.1 8.6 For the geometry used, the stress at failure is calculated from 225P B Pa where P is in newtons and B is in metres. (Note that this is an empirical formula so the units do not balance.) i. Use the 'Beam in pure bending - through-thickness edge crack' geometry in the K- calculator to calculate the value of K at failure for the three samples. (10 marks) ii. In order for a valid fracture toughness value to be obtained, both the sample thickness B and the final crack length a should satisfy B, a 2.5 KQ σyield 2 where KQ is the estimated toughness value of K at failure, and σ yield is the yield strength of the material. In this case σ yield = 620 MPa. Calculate whether the samples are sufficiently thick (i.e. whether B is large enough) to meet this criterion. Are the final crack lengths acceptable? (10 marks)
Beam in pure bending - through-thickness edge crack
Calculate:
KI
Material properties:
O Critical crack length
O Critical stress
○ KIC
KIC:
31.33 MPa Vm
Geometry dimensions:
Width (2W):
40.000 mm
Crack length (2a):
0.100 mm
Y:
1.00
Loading:
Stress:
2500.00 MPa
KI:
31.33 MPa Vm
Reserve factor on the load:
1.00
Transcribed Image Text:Beam in pure bending - through-thickness edge crack Calculate: KI Material properties: O Critical crack length O Critical stress ○ KIC KIC: 31.33 MPa Vm Geometry dimensions: Width (2W): 40.000 mm Crack length (2a): 0.100 mm Y: 1.00 Loading: Stress: 2500.00 MPa KI: 31.33 MPa Vm Reserve factor on the load: 1.00
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