A viscous fluid flows past a flat plate such that the boundary layer thickness at a distance 1.3 m from the leading edge is 12 mm. Determine the boundary layer thickness at 1 m from the leading edge. Assume laminar flow. a. 10.5 mm b. 3.5 mm c. 6.6 mm d. 5.7 mm < > A gas at 20 °C and 1 atm flows at 1.83 m/s past a thin flat plate. At x = 91.4 cm, the boundary layer thickness is 1.4 cm. Assuming laminar flow, which of the gases in the table below is this likely to be? Molecular Specific-heat Power-law Gas weight R. K pg. N/m . N-s/m² m² ratio exponent a H₂ 2.016 4124 0.822 9.05 E-6 1.08 E-04 1.41 0.68 Hel 4.003 2077 1.63 1.97 E-5 L18E-04 1.66 0.67 H₂O 18.02 461 7.35 1.02 E-5 L36E-05 1.33 1.15 Ar 39.944 208 16.3 2.24 E-5 1.35 E-05 1.67 0.72 Dry air 28.96 287 11.8 1.80 E-5 L49 E-05 1.40 0.67 CO 44.01 189 17.9 1.48 E-5 8.09 E-06 1.30 0.79 28.01 297 114 1.82 E-5 1.56 E-05 1.40 0.71 N 28.02 297 11.4 1.76 E-5 151E-05 1.40 0.67 0₂ 32.00 260 13.1 2.00 E-5 L50E-05 1.40 0.69 30.01 277 12.1 1.90 E-5 1.52E-05 1.40 0.78 N₂O 44.02 189 17.9 1.45 E-5 7.93 E-06 1.31 0.89 Cl 70.91 117 28.9 1.03 E-5 3.49 E-06 1.34 1.00 CH. 16.04 518 6.54 1.34 E-5 201 E-05 1.32 0.87 "The power-law curve fit. Eq. (1.27), (77293). fits these gases to within 4 percent in the range 2507 1000 K. The temperature must be in kelvins. a. N20 b. CO2 C. H20 d. CO < >
A viscous fluid flows past a flat plate such that the boundary layer thickness at a distance 1.3 m from the leading edge is 12 mm. Determine the boundary layer thickness at 1 m from the leading edge. Assume laminar flow. a. 10.5 mm b. 3.5 mm c. 6.6 mm d. 5.7 mm < > A gas at 20 °C and 1 atm flows at 1.83 m/s past a thin flat plate. At x = 91.4 cm, the boundary layer thickness is 1.4 cm. Assuming laminar flow, which of the gases in the table below is this likely to be? Molecular Specific-heat Power-law Gas weight R. K pg. N/m . N-s/m² m² ratio exponent a H₂ 2.016 4124 0.822 9.05 E-6 1.08 E-04 1.41 0.68 Hel 4.003 2077 1.63 1.97 E-5 L18E-04 1.66 0.67 H₂O 18.02 461 7.35 1.02 E-5 L36E-05 1.33 1.15 Ar 39.944 208 16.3 2.24 E-5 1.35 E-05 1.67 0.72 Dry air 28.96 287 11.8 1.80 E-5 L49 E-05 1.40 0.67 CO 44.01 189 17.9 1.48 E-5 8.09 E-06 1.30 0.79 28.01 297 114 1.82 E-5 1.56 E-05 1.40 0.71 N 28.02 297 11.4 1.76 E-5 151E-05 1.40 0.67 0₂ 32.00 260 13.1 2.00 E-5 L50E-05 1.40 0.69 30.01 277 12.1 1.90 E-5 1.52E-05 1.40 0.78 N₂O 44.02 189 17.9 1.45 E-5 7.93 E-06 1.31 0.89 Cl 70.91 117 28.9 1.03 E-5 3.49 E-06 1.34 1.00 CH. 16.04 518 6.54 1.34 E-5 201 E-05 1.32 0.87 "The power-law curve fit. Eq. (1.27), (77293). fits these gases to within 4 percent in the range 2507 1000 K. The temperature must be in kelvins. a. N20 b. CO2 C. H20 d. CO < >
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:A viscous fluid flows past a flat plate such that
the boundary layer thickness at a distance 1.3
m from the leading edge is 12 mm. Determine
the boundary layer thickness at 1 m from the
leading edge. Assume laminar flow.
a. 10.5 mm
b. 3.5 mm
c. 6.6 mm
d. 5.7 mm
< >
Transcribed Image Text:A gas at 20 °C and 1 atm flows at 1.83 m/s past
a thin flat plate. At x = 91.4 cm, the boundary
layer thickness is 1.4 cm. Assuming laminar
flow, which of the gases in the table below is
this likely to be?
Molecular
Specific-heat Power-law
Gas
weight R. K pg. N/m . N-s/m² m²
ratio
exponent a
H₂
2.016
4124
0.822
9.05 E-6
1.08 E-04
1.41
0.68
Hel
4.003
2077
1.63
1.97 E-5
L18E-04
1.66
0.67
H₂O
18.02
461
7.35
1.02 E-5
L36E-05
1.33
1.15
Ar
39.944
208
16.3
2.24 E-5
1.35 E-05
1.67
0.72
Dry air
28.96
287
11.8
1.80 E-5
L49 E-05
1.40
0.67
CO
44.01
189
17.9
1.48 E-5
8.09 E-06
1.30
0.79
28.01
297
114
1.82 E-5
1.56 E-05
1.40
0.71
N
28.02
297
11.4
1.76 E-5
151E-05
1.40
0.67
0₂
32.00
260
13.1
2.00 E-5
L50E-05
1.40
0.69
30.01
277
12.1
1.90 E-5
1.52E-05
1.40
0.78
N₂O
44.02
189
17.9
1.45 E-5
7.93 E-06
1.31
0.89
Cl
70.91
117
28.9
1.03 E-5
3.49 E-06
1.34
1.00
CH.
16.04
518
6.54
1.34 E-5
201 E-05
1.32
0.87
"The power-law curve fit. Eq. (1.27), (77293). fits these gases to within 4 percent in the range 2507
1000 K. The temperature must be in kelvins.
a.
N20
b. CO2
C.
H20
d. CO
< >
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