15. An empty flask has a mass of 48.293g and 48.612g when filled with acetone vapor at 80°C and 728mmHg. If the volume of the flask is 227.2mL, what is the molecular weight of the acetone? a. 43.7497kg/kmol b. 38.6978kg/kmol c. 42.4760kg/kmol d. 43.8075kg/kmol
15. An empty flask has a mass of 48.293g and 48.612g when filled with acetone vapor at 80°C and 728mmHg. If the volume of the flask is 227.2mL, what is the molecular weight of the acetone? a. 43.7497kg/kmol b. 38.6978kg/kmol c. 42.4760kg/kmol d. 43.8075kg/kmol
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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can you show me how did it get the universal gas constant (R)?
![15. An empty flask has a mass of 48.293g and 48.612g
when filled with acetone vapor at 80°C and 728mmHg. If
the volume of the flask is 227.2mL, what is the molecular
weight of the acetone?
a. 43.7497kg/kmol
b. 38.6978kg/kmol
c. 42.4760kg/kmol
d. 43.8075kg/kmol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F51f2df20-f0c7-4d6b-adc0-24aeb2e88d5a%2Fb80103be-398b-45bb-bcae-6ab5e3663cb4%2Fcens95q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:15. An empty flask has a mass of 48.293g and 48.612g
when filled with acetone vapor at 80°C and 728mmHg. If
the volume of the flask is 227.2mL, what is the molecular
weight of the acetone?
a. 43.7497kg/kmol
b. 38.6978kg/kmol
c. 42.4760kg/kmol
d. 43.8075kg/kmol
![Salut ion:
ma88 (m)= 0• 000 319 kg
P = 720 mm Hg = 97.0587 KPa
T=
353.15 K
V = 0.227 2 L = 0.0002272 m3
univessal Gas Constant (R) = 0.134 K8/Kmol k
%3D
we know that,
PV = nRT
(n+ moles)
%3D
97.0507X00002272= nx8.314 X353·15
On Balving,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F51f2df20-f0c7-4d6b-adc0-24aeb2e88d5a%2Fb80103be-398b-45bb-bcae-6ab5e3663cb4%2Fufv1j55b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Salut ion:
ma88 (m)= 0• 000 319 kg
P = 720 mm Hg = 97.0587 KPa
T=
353.15 K
V = 0.227 2 L = 0.0002272 m3
univessal Gas Constant (R) = 0.134 K8/Kmol k
%3D
we know that,
PV = nRT
(n+ moles)
%3D
97.0507X00002272= nx8.314 X353·15
On Balving,
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