Suppose an electron (q = - e= - 1.6× 10¬19C,m=9.1×10¬3' kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K = -U 1 Since K = mv² and using the formula for potential energy above, we arrive at an equation for speed: 2 v ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=

Suppose an electron (q = - e= - 1.6× 10¬19C,m=9.1×10¬3' kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K = -U 1 Since K = mv² and using the formula for potential energy above, we arrive at an equation for speed: 2 v ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Suppose an electron (q= -e= -1.6x 10-19 C.m=9.1×10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 v. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U- Assuming all potential energy U is converted to kinetic energy K. K+U=0 K--U Since K=mv and using the formula for potential energy above, we arrive at an equation for speed: 1/2 Plugging in values, the value of the electron's speed is: x 10' m/s
An electron start at rest at a spot where the electric potential is 0 V. What will be its speed when it reaches a point where the potential is 1000 V?
Calculate the speed of an electron (in m/s) after it accelerates from rest through a potential difference of 140 V. 7.02e25 m/s The speed of the electron v can be found using the kinetic energy equation, K = 1/2(mv^2). The change in kinetic energy is equal to the work done on the electron, K = W = -U = -qV. Using those two equations, solve for the speed v in terms of the potential V and constants. Remember that the mass of an electron is 9.1e-31 kg and its charge is 1.6e-19 C. Submit Answer Incorrect. Tries 1/2 Previous Tries
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Answer must be in standard form scientific notation with SI units that do not have prefixes except for kg. Provide the answer with the correct amount of significant figures. Thank you so much I greatly appreciate it
A proton, an electron, and an alpha particle (of charge +2e) form an equilateral triangle of side length 3.77×10-10 m. What is the electric potential energy of the three-particle system?
Two charges, qi =-14.0 mC and q2 =8.4 mC are separated by distance r =6.6 m. What is the change in the electric potential energy of the system of these two charges if the separation changes to 0.7r? Provide your answer in kilojoules, with a precision of one place after the decimal.
Q2 For the system shown in figure. (Q = 1 μC, a = 0.2 m). 9₁=+Q 92=+Q 94-Q 93=+Q a (a) Find the work done (stored potential energy) to assemble the system. What is the physical meaning of the resulted potential energy? (b) Find the electric potential at the point (P), which is located at the center of the square.