Suppose an electron (q= - e= -1.6x 10-19 C,m=9.1×10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential vabis related by the equation:
Suppose an electron (q= - e= -1.6x 10-19 C,m=9.1×10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential vabis related by the equation:
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter26: Electric Potential
Section: Chapter Questions
Problem 67PQ: A charged particle is moved in a uniform electric field between two points, A and B, as depicted in...
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![Suppose an electron (g= - e= -1.6x 10-19 C ,m=9.1× 10-31 kg) is accelerated from rest through a potential
difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two
significant figures.
The potential energy U is related to the electron charge (-e) and potential vab is related by the equation:
U=
Assuming all potential energy U is converted to kinetic energy K,
K + U = 0
K = -U
Since K=mv and using the formula for potential energy above, we arrive at an equation for speed:
v = (
1/2
Plugging in values, the value of the electron's speed is:
V=
x 107 m/s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe0d8a936-2b9f-4f86-96d2-fdf76a1f3b55%2F3330b61b-d233-4439-bf7e-f1d3bf8fc6d6%2Fnxm7y6_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose an electron (g= - e= -1.6x 10-19 C ,m=9.1× 10-31 kg) is accelerated from rest through a potential
difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two
significant figures.
The potential energy U is related to the electron charge (-e) and potential vab is related by the equation:
U=
Assuming all potential energy U is converted to kinetic energy K,
K + U = 0
K = -U
Since K=mv and using the formula for potential energy above, we arrive at an equation for speed:
v = (
1/2
Plugging in values, the value of the electron's speed is:
V=
x 107 m/s
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