Suppose an electron (q= - e= -1.6x 10-19 C,m=9.1×10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential vabis related by the equation:

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter26: Electric Potential
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Problem 67PQ: A charged particle is moved in a uniform electric field between two points, A and B, as depicted in...
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Suppose an electron (g= - e= -1.6x 10-19 C ,m=9.1× 10-31 kg) is accelerated from rest through a potential
difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two
significant figures.
The potential energy U is related to the electron charge (-e) and potential vab is related by the equation:
U=
Assuming all potential energy U is converted to kinetic energy K,
K + U = 0
K = -U
Since K=mv and using the formula for potential energy above, we arrive at an equation for speed:
v = (
1/2
Plugging in values, the value of the electron's speed is:
V=
x 107 m/s
Transcribed Image Text:Suppose an electron (g= - e= -1.6x 10-19 C ,m=9.1× 10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential vab is related by the equation: U= Assuming all potential energy U is converted to kinetic energy K, K + U = 0 K = -U Since K=mv and using the formula for potential energy above, we arrive at an equation for speed: v = ( 1/2 Plugging in values, the value of the electron's speed is: V= x 107 m/s
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