Ernst Rutherford discovered the atomic nucleus by shooting alpha particles (helium nuclei) at gold atoms. An alpha particle (charge +2e, mass M) is approaching a gold nuclei (charge +Q) straight on. The alpha particle slows down and turns around at point B which is a distance W from the gold nuclei. Point A is 3W from point B. What is the kinetic energy of the alpha particle as it passes point A? Treat the gold nuclei as stationary. Hint: label the lengths. A OKQe W O 6KQe W O 3 KQe 2 W KQe 2W O 2KQe W B +Q

Ernst Rutherford discovered the atomic nucleus by shooting alpha particles (helium nuclei) at gold atoms. An alpha particle (charge +2e, mass M) is approaching a gold nuclei (charge +Q) straight on. The alpha particle slows down and turns around at point B which is a distance W from the gold nuclei. Point A is 3W from point B. What is the kinetic energy of the alpha particle as it passes point A? Treat the gold nuclei as stationary. Hint: label the lengths. A OKQe W O 6KQe W O 3 KQe 2 W KQe 2W O 2KQe W B +Q

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

E7P7
1. How do you find the gravitational potential of two masses for any position around them that is outside the masses? Specifically, take the Earth and the Moon as an example. We need big masses like these because G is so small. Gravity is very weak. When we do electricity, we can work with smaller amounts of matter and smaller distances because electrical forces are stronger than gravitational forces. Here are the numbers https://nssdc.gsfc.nasa.gov/planetary/factsheet/moonfact.html MEarth = 5.97 × 1024 kg (Mass of Earth) MMoon = 7.35 × 1022 kg (mass of Moon) RE-M = 3.85 × 108 m (average separation of Earth and Moon centers) REarth = 6.378 × 106 m (radius of Earth) RMoon = 1.738 × 106 m (radius of Moon)
Can I have help with this problem?
Find the force vector F on an object of mass m the uniform gravitational field when it is at height z = 0. The +z direction is up. Express vector force in terms of m, z. g. and k, where k is the unit vector in the +z direction. To create the k character: In the equation editor window, select "More", then select "Vectors", and you will find what you need. To write out a vector: for example, if the answer has both x and y components, you would answer in the format Fi + Fj F(z) = -mgk Now find the gravitational potential energy U(z) of the object when it is at an arbitrary height z. Take zero potential to be at position z=0. Keep in mind that the potential energy is a scalar, not a vector. Express U(z) in terms of m. z. and g. U(2)= In what direction does the object accelerate when released with initial velocity upward? downward Oupward or downward depending on the initial mass m. upward or downward depending on the initial velocity upward Now consider the analogous case of a particle…
3a. What is the potential energy U of this lightning bolt? U = 310 Joules of the square? Find 30 (1.0x10) 3b. If all this energy where to be converted to kinetic energy, what would be the speed of a m = 1000 kg car. Vf = r16 = 34 = m/s 16. These charges are numbered as: raw the re Redraw the rectangle with the actual charges (evaluate 2q1, 492, etc.) 16a. What is the distance between the indicated pairs of charges. Find these in meters. r24 = r26 = 15 = 35 = P278Volt Volts 1 2 3 MI 4 5 6 16b. Starting with all the charges at ∞, what is the potential at the upper left corner, and how much work is done to put the charge at the upper left corner? V₁ = 05 W₁ = Joules ainT V3 = V13 + V23 = srpC = 10-12 Cond m 16c. What is the potential at the location of 2, due to the previous charges? How much work is done to bring in the 2nd charge? Make sure you use the correct distance. V₂ = V12 = Volts W₂ = 16d. What is the potential at the location of 3, due to the previous charges? How much work is…
Q8. Assume the electric potential at the negatively charged plate is zero. Clearly show all work! a) A charged particle A with charge + 0.020 C and mass 3.0x10-8 kg is at rest as shown next to the positive plate which has electric potential of 120 V. What is its kinetic energy when it reaches the negatively charged plate? What is its speed? b) Another charged particle B with charge + 0.060 C and mass 3.0x10-8 kg is at rest as shown. What is its kinetic energy when it reaches the negatively charged plate? What is its speed? c) A third charged particle C (not shown) with charge 0.070 C and mass 3.0x10-8 kg is at rest in the middle of the two parallel plates. How much work is needed to move it to the positively charged plate? Is the work positive or negative? 0 0 0 0 0 0 0 0
How much work must you do to move an electron from A to B? The rectangle is 19.5 cm high and 31.6 cm wide. Remember that negative work means that we can get work out of the process.
A particle that carries a net charge of -41.8 µC is held in a constant electric field that is uniform over the entire region. The electric field vector is oriented 25.2° clockwise from the vertical axis, as shown in the figure. If the magnitude of the electric field is 7.82 N/C, how much work is done by the electric field as the particle is made to move a distance of d = 0.556 m straight up? work: What is the potential difference AV between the particle's initial and final positions? AV = J V
Two charges, qi =-14.0 mC and q2 =8.4 mC are separated by distance r =6.6 m. What is the change in the electric potential energy of the system of these two charges if the separation changes to 0.7r? Provide your answer in kilojoules, with a precision of one place after the decimal.
An alpha particle, which has charge 3.204 ✕ 10−19 C, is moved from point A, where the electric potential is 2.30 ✕ 103 J/C, to point B, where the electric potential is 3.50 ✕ 103 J/C. Calculate the work in electron volts done by the electric field on the alpha particle.
A particle of charge Q and mass M enters an electric field with speed Vo and is slowed down to zero speed over a distance d. Find the work done on the particle by the electric force. QEd -MV0²/2 MV ²/2 Fed
Two protons are at a distance of 2.7 X 10-15 m from each other. What is the potential energy of the two protons? Use scientific/exponential notation to input your answer. Eg., 0.0001 can be written as 1.0e-4 or as 1.0E-4. Spaces not allowed. Answer format: Example: 2.1e1 J