A particle that carries a net charge of -41.8 µC is held in a constant electric field that is uniform over the entire region. The electric field vector is oriented 25.2° clockwise from the vertical axis, as shown in the figure. If the magnitude of the electric field is 7.82 N/C, how much work is done by the electric field as the particle is made to move a distance of d = 0.556 m straight up? work: What is the potential difference AV between the particle's initial and final positions? AV = J V

A particle that carries a net charge of -41.8 µC is held in a constant electric field that is uniform over the entire region. The electric field vector is oriented 25.2° clockwise from the vertical axis, as shown in the figure. If the magnitude of the electric field is 7.82 N/C, how much work is done by the electric field as the particle is made to move a distance of d = 0.556 m straight up? work: What is the potential difference AV between the particle's initial and final positions? AV = J V

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Positive electric charge QQ is distributed uniformly along a thin rod of length 2a. The rod lies…

A: The electric potential at x=L (L>+a) along the length of rod is found by integrating the point…

Q: At point P, what is the electric potential? What is the potential energy of an electron? At point…

Q: Given three points: (q1= 3.0mC, q2= -4.5mC, and q3= 5.5mC). Q1 and q2 are located .06m apart, q1 and…

A: Given data: Charges at 1,2 and 3 are, Q1=3.0 mCQ2=-4.5 mCQ3=5.5 mC

Q: E (a) Calculate is the change in PE when an electron moves through an electric field, E = 50 N/C,…

A: A. PE change = q(E×d)PE change = -1.6 × 10-19 (50×6)PE change = -4.8 × 10-17 B. The mechanical…

Q: Consider two points in an electric field. The potential at point 1, V1, is 48 V. The potential at…

Q: ven the system below, calculate the electric potential energy for the group of charges. Q1 =…

Q: A particle that carries a net charge of -59.8 μC is held in a constant electric field that is…

A: Q = charge = -59.8μc θ = angle from vertical =25.2 E = electric field =6.32N/C d = distance…

Q: Consider two points in an electric field. The potential at point 1, V1 is 33 V. The potential at…

A: Electric potential at point 1 is Electric potential at point 2 is A proton moves from point 1 to…

Q: 1. -2q As shown in the diagram, two charges +q and -2q are placed on opposite corners of a square…

A: Given that:- q=1.1×10^-9C

Q: V E (a) Calculate is the change in PE when an electron moves through an electric field, E = 60 N/C,…

Q: The rectangle shown below has sides 5.0 cm and 8.0 cm. The charges are q₁ = +6.0 µC and 92 = +9.0…

Q: Two point charges each of magnitude 3.00 µC are located on the y axis as shown in figure below. a)…

A: Given: Charges Q1 = Q2 = 3.00 μC are located as shown in figure To determine: a) The electric…

Q: The amount of work you have to do to move a charge q from point Pi to point P2 through a small…

A: Work done on the charge is given by the expressionW=-qE∆rcosφφ is the angle between the displacement…

Q: A SYSTEM OF TWO ELECTRIC CHARGES b (in J) 92 91 What is the potential energy of this system of two…

Q: When an object with an electric charge of −0.050 mC is 9.0 m away from an object with an electric…

Q: The figure below shows a charged particle, with a charge of q = +43.0 nC, that moves a distance of d…

Q: Consider the same charge q=1C moving in the same field, E=2 N/C in the x direction, between the same…

A: The force on the charge can be calculated as below,

Q: An alpha particle, which has charge 3.20 x 10-19 c, is moved from point A, where the electric…

Q: Two protons are at rest, one at the origin, and the other at the location (3.00 A, 0). An alpha…

Q: the function: V = ax+By² describes the electric potential in a specific region in space assume…

Q: 1. V E (a) Calculate is the change in PE when an electron moves through an electric field, E = 50…

A: PE change = q(E×d) PE change = -1.6 × 10-19 (50×6) PE change = -4.8 × 10-17 J (a) The mechanical…

Q: Two charges +q and -2q are placed on opposite corners of a square with sides 3 cm. If q = 1.5 x 10-9…

A: Given data: Q1 = +q = +1.5×10-9 C Q2 = -2q = -3×10-9 C Side of square (r) = 3 cm = 0.03 m Coulomb…

Q: Four identical charged particles (q=+12.0 µC) are located on the corners of a rectangle as shown in…

Q: The electric potential in a particular area varies with position as V(x) = ax2 - bx + c, where a =…

A: The electric field strength is the negative of the potential gradient.

Q: A particle has a charge of +1.40 µC and moves from point A to point B, a distance of 0.170 m. The…

Q: A line charge of 3L with nonuniform charge density A(x) = ax is placed along the x-axis as shown in…

Q: Ernst Rutherford discovered the atomic nucleus by shooting alpha particles (helium nuclei) at gold…

Q: In the science fiction story "The little prince is an android" a second journey of the character…

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

A particle that carries a net charge of -41.8 µC is held in a
constant electric field that is uniform over the entire region.
The electric field vector is oriented 25.2° clockwise from the
vertical axis, as shown in the figure. If the magnitude of the
electric field is 7.82 N/C, how much work is done by the
electric field as the particle is made to move a distance of
d = 0.556 m straight up?
work:
What is the potential difference AV between the particle's
initial and final positions?
AV =
J
V

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Determining the given values and objectives

VIEW

Step 2: Calculating the work done

VIEW

Step 3: Calculating the potential difference

VIEW

Solution

VIEW

Step by step

Solved in 4 steps with 5 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

The figure below shows a charged particle, with a charge of q = +39.0 nC, that moves a distance of d = 0.190 m from point A to point B in the presence of a uniform electric field E of magnitude 255 N/C, pointing right. (a) What is the magnitude (in N) and direction of the electric force on the particle? (b) What is the work (in J) done on the particle by the electric force as it moves from A to B? (c) What is the change of the electric potential energy (in J) as the particle moves from A to B? (The system consists of the particle and all its surroundings.) PEB − PEA = (d) What is the potential difference (in V) between A and B? VB − VA =
Please give me answer very fast in 5 min sub
HELP
Topic: Electrical Potential A point charge q1 = +2.40 µC is held stationary at the origin. A second point charge q2 = -4.30 µC moves from the point x = 0.150 m, y = 0 m to the point x = 0.250 m. How much work is done by the electric force on q2?
Consider two points in an electric field. The potential at point 1, V1, is 29 V. The potential at point 2, V2, is 173 V. An electron at rest at point 1 is accelerated by the electric field to point 2. Write an equation for the change of electric potential energy ΔU of the electron in terms of the symbols given. Find the numerical value of the change of the electric potential energy in electron volts (eV). Express v2, the speed of the electron at point 2, in terms of ΔU, and the mass of the electron me.
= Two point particles have equal charge q 1100 esu and different masses, m₁ = 25 gr and m₂ = 65 gr, are confined to move freely along the x axis. Note that esu is the unit of electric charge when working with units of mass in grams and distance in centimeters. = The electrical force between the particles is a repelling force which is derived from the potential energy function U(x1, x2) of the two-particles system. U(x1, x2) depends only on the distance of the particles and is given by U(x1, x2) - q2 | x2 − x1| At t = 0) the particle of mass m2 is at rest at the origin (x2 = 0), and the particle of mass m₁ begins to move from point x1 = 76 cm with velocity vo 134 cm/s towards particle m2. = a. What is the location of the center of mass (in cm) at t - 0? -21. b. What is the location of the center of mass (in cm) at t = 0.4 sec? -6.2 c. What will be the minimum distance (in cm) between the two particles? 6.46 X d. Once the distance between the particles is minimal, what will be the speed…
The rectangle in the figure is 3 sidescapped by 5.0cm and 15cm, etq1 = −5μCetq2 = + 2.0μC. IfV = 0 at infinity, what is the electric potential (a) at corner A? (b) at corner B? (c) How much work does it take to move a third load q3 = +3.0 μC from point B to point A on the diagnonal of the rectangle? (d) Does this work increase or decrease the potential electrical energy of the three-load system? Is it greater than, less than or equivalent to the work required to move q3 on trajectories that are inside the rectangle but not on the diagnostic? (f) outside the rectangle? Please show formulas, thank you
so the distance is from -3 to 5 cm which is 8cm or .08m. I did parts a-e and need help for parts f-h. This is what I have so far: a: V1=1000V b: 3.2e^-16 J c. potential energy; no work needed to move particle as it leaves electric field d. 3.2e^-16 J e. m1<m2<m3<m4, v1>v2>v3>v4 f. distance =.08m -time takes particle 1 hit detector: .98e^-6 sec ---> .08m/.98e^-6 s= 8.16e^4 m/s -time takes particle 2 hit detector: 1.4e^-6 s --> .08m/1.4e^-6 s= 5.71e^4 m/s -time takes particle 3 hit detector: 1.7e^-6 s --> .08m/1.7^-6 s= 4.7053^4 m/s -time takes particle 4 hit detector: 1.96^-6 s --> .08m/1.96^-6 s= 4.082e^4 m/s I am not sure if i Made any mistakes so please let me know if i DO!
Consider a certain amount of a conducting liquid sprayed into 650 equal spherical drops. Each drop is charged to the same electric potential of 2.5 V (relative to the infinity where potential is zero). If all these 650 drops are combined into one large spherical drop, what is the electric potential of this large drop? The electric potential of the large drop, V = Units Select an answer ✓
= A point charge Q1 = +5.8 µC is fixed in space, while a point charge Q2 = +2.8 nC, with mass 6.3 µg, is free to move around nearby. Calculate the electric potential energy of the system, in joules, when Q2 is located 0.42 m from Q₁. If Q2 is released from rest at a point 0.42 m from Q₁, what will be its speed, in meters per second, when it is 0.79 m from Q₁? m/s
Consider two points in an electric field. The potential at point 1, V1, is 31 V. The potential at point 2, V2, is 191 V. An electron at rest at point 1 is accelerated by the electric field to point 2. a) write an equation for the change of electric potential energy of the electron in terms of the symbols given. b) Express v2, the speed of the electron at point 2, in terms of electric potential energy, and the mass of the electron, me.
The figure below shows a small, charged sphere, with a charge of q = +38.0 nC, that moves a distance of d = 0.171 m from point Ato point B in the presence of a uniform electric field E of magnitude 280 N/C, pointing right. (a) What is the magnitude (in N) and direction of the electric force on the sphere? magnitude n? (b) What is the work (in J) done on the sphere by the electric force as it moves from A to B? J?? (C) What is the change of the electric potential energy (in J) as the sphere moves from A to B? (The system consists of the sphere and all its surroundings.) PEB − PEA = ? J (D)What is the potential difference (in V) between A and B? VB − VA = ? V