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= Two point particles have equal charge q 1100 esu and different masses, m₁ = 25 gr and m₂ = 65 gr, are confined to move freely along the x axis. Note that esu is the unit of electric charge when working with units of mass in grams and distance in centimeters. = The electrical force between the particles is a repelling force which is derived from the potential energy function U(x1, x2) of the two-particles system. U(x1, x2) depends only on the distance of the particles and is given by U(x1, x2) - q2 | x2 − x1| At t = 0) the particle of mass m2 is at rest at the origin (x2 = 0), and the particle of mass m₁ begins to move from point x1 = 76 cm with velocity vo 134 cm/s towards particle m2. = a. What is the location of the center of mass (in cm) at t - 0? -21. b. What is the location of the center of mass (in cm) at t = 0.4 sec? -6.2 c. What will be the minimum distance (in cm) between the two particles? 6.46 X d. Once the distance between the particles is minimal, what will be the speed (in cm/sec) of the particle m₁ relative to the laboratory frame? 37.2 e. After certain time, the particles will repel each other and move away so that the force between them can be neglected. What will be the velocity (in cm/sec) of the particle m₁ relative to the laboratory frame in this case? 66.8 X f. What will be the velocity (in cm/sec) of charge m2 relative to the laboratory then (after neglecting the force)? 77.2 X

= Two point particles have equal charge q 1100 esu and different masses, m₁ = 25 gr and m₂ = 65 gr, are confined to move freely along the x axis. Note that esu is the unit of electric charge when working with units of mass in grams and distance in centimeters. = The electrical force between the particles is a repelling force which is derived from the potential energy function U(x1, x2) of the two-particles system. U(x1, x2) depends only on the distance of the particles and is given by U(x1, x2) - q2 | x2 − x1| At t = 0) the particle of mass m2 is at rest at the origin (x2 = 0), and the particle of mass m₁ begins to move from point x1 = 76 cm with velocity vo 134 cm/s towards particle m2. = a. What is the location of the center of mass (in cm) at t - 0? -21. b. What is the location of the center of mass (in cm) at t = 0.4 sec? -6.2 c. What will be the minimum distance (in cm) between the two particles? 6.46 X d. Once the distance between the particles is minimal, what will be the speed (in cm/sec) of the particle m₁ relative to the laboratory frame? 37.2 e. After certain time, the particles will repel each other and move away so that the force between them can be neglected. What will be the velocity (in cm/sec) of the particle m₁ relative to the laboratory frame in this case? 66.8 X f. What will be the velocity (in cm/sec) of charge m2 relative to the laboratory then (after neglecting the force)? 77.2 X

Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
Problem 16OQ: A filament running along the x axis from the origin to x = 80.0 cm carries electric charge with...
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= Two point particles have equal charge q 1100 esu and different masses, m₁ = 25 gr and m₂ = 65 gr, are confined to move freely along the x axis. Note that esu is the unit of electric charge when working with units of mass in grams and distance in centimeters. = The electrical force between the particles is a repelling force which is derived from the potential energy function U(x1, x2) of the two-particles system. U(x1, x2) depends only on the distance of the particles and is given by U(x1, x2) - q2 | x2 − x1| At t = 0) the particle of mass m2 is at rest at the origin (x2 = 0), and the particle of mass m₁ begins to move from point x1 = 76 cm with velocity vo 134 cm/s towards particle m2. = a. What is the location of the center of mass (in cm) at t - 0? -21. b. What is the location of the center of mass (in cm) at t = 0.4 sec? -6.2 c. What will be the minimum distance (in cm) between the two particles? 6.46 X d. Once the distance between the particles is minimal, what will be the speed (in cm/sec) of the particle m₁ relative to the laboratory frame? 37.2 e. After certain time, the particles will repel each other and move away so that the force between them can be neglected. What will be the velocity (in cm/sec) of the particle m₁ relative to the laboratory frame in this case? 66.8 X f. What will be the velocity (in cm/sec) of charge m2 relative to the laboratory then (after neglecting the force)? 77.2 X
Transcribed Image Text:= Two point particles have equal charge q 1100 esu and different masses, m₁ = 25 gr and m₂ = 65 gr, are confined to move freely along the x axis. Note that esu is the unit of electric charge when working with units of mass in grams and distance in centimeters. = The electrical force between the particles is a repelling force which is derived from the potential energy function U(x1, x2) of the two-particles system. U(x1, x2) depends only on the distance of the particles and is given by U(x1, x2) - q2 | x2 − x1| At t = 0) the particle of mass m2 is at rest at the origin (x2 = 0), and the particle of mass m₁ begins to move from point x1 = 76 cm with velocity vo 134 cm/s towards particle m2. = a. What is the location of the center of mass (in cm) at t - 0? -21. b. What is the location of the center of mass (in cm) at t = 0.4 sec? -6.2 c. What will be the minimum distance (in cm) between the two particles? 6.46 X d. Once the distance between the particles is minimal, what will be the speed (in cm/sec) of the particle m₁ relative to the laboratory frame? 37.2 e. After certain time, the particles will repel each other and move away so that the force between them can be neglected. What will be the velocity (in cm/sec) of the particle m₁ relative to the laboratory frame in this case? 66.8 X f. What will be the velocity (in cm/sec) of charge m2 relative to the laboratory then (after neglecting the force)? 77.2 X
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