1. Two persons were practicing social distancing to alleviate the spread of COVID-19. Social distancing requires a minimum of 3 feet distance from person to person. However, due to their eagerness to share some rumors, the two persons decided to approach each other and now within the intimate distance (12 inches). If person A weighs 60 kg. and person B weighs 68 kg, determine the work done for this act. Take G = 6.67408 × 10-1" m² kg~'s-2. A. 6.8076 ergs B. 8.0766 ergs C. 5.9559 ergs D. 5.5599 ergs

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1. Two persons were practicing social distancing to alleviate the spread of COVID-19. Social distancing requires a minimum of
3 feet distance from person to person. However, due to their eagerness to share some rumors, the two persons decided to
approach each other and now within the intimate distance (12 inches). If person A weighs 60 kg. and person B weighs 68 kg,
determine the work done for this act. Take G = 6.67408 x 10-11 m³ kg¬'s-2.
A. 6.8076 ergs
B. 8.0766 ergs
C. 5.9559 ergs
D. 5.5599 ergs
2. Find the moment of mass from the x-axis for y = x In(x) – 3x and y = 1 bounded by x = 3 and x = 6. The surface
density is equal to 0.37 kg/units'.
A. 24.0793 kg.
В. -38.6209 kg
C. 27.8043 kg.
D. -36.8902 kg.
3. In 2019, SCUBA divers from Mexico explores the Atlantic Ocean (64 lb/ft) and finds a circular clock thought to be the ancient
remnants of the legendary Atlantis. If the clock measures 1.3 ft. in diameter and depth is measured to be 1250 ft. from the
surface to the center of this clock, what force is experienced by the object?
A. 251327.4123 lb:
B. 53092.9159 lb
C. 16900 lbr
D. 106185.8317 lb;
4. A mixture of chemicals in a variable volume batch reactor (order = 3) compresses during its chemical reaction [x =
0.90 M-?min-1). The compression coefficient (e) is equal to 1.6. If the reaction proceeds until 70% completion, determine
the capacity of the reactor for an initial concentration of 0.55 mol/L fed at a rate of 12.20 L/min.
A. 185.5346L
В. 421.7284L
C. 31.36823 L
D. 12.9728 L
5. Calculate the work for the expansion of 3 moles of B,H; at 40°C from 2.74 L to 3.89 L using van der Waals equation. The
correction for intermolecular forces (a) is 6.048 bar L/mol? and the adjustment factor of thevolume (b) is 0.07437 L/mol.
The general equation for van der Waals is written below:
n21
+ a
= RT
A. 2352.2376J
B. -2352.2376 J
C. 2118.1071J
D. -2118.1071 J
Transcribed Image Text:1. Two persons were practicing social distancing to alleviate the spread of COVID-19. Social distancing requires a minimum of 3 feet distance from person to person. However, due to their eagerness to share some rumors, the two persons decided to approach each other and now within the intimate distance (12 inches). If person A weighs 60 kg. and person B weighs 68 kg, determine the work done for this act. Take G = 6.67408 x 10-11 m³ kg¬'s-2. A. 6.8076 ergs B. 8.0766 ergs C. 5.9559 ergs D. 5.5599 ergs 2. Find the moment of mass from the x-axis for y = x In(x) – 3x and y = 1 bounded by x = 3 and x = 6. The surface density is equal to 0.37 kg/units'. A. 24.0793 kg. В. -38.6209 kg C. 27.8043 kg. D. -36.8902 kg. 3. In 2019, SCUBA divers from Mexico explores the Atlantic Ocean (64 lb/ft) and finds a circular clock thought to be the ancient remnants of the legendary Atlantis. If the clock measures 1.3 ft. in diameter and depth is measured to be 1250 ft. from the surface to the center of this clock, what force is experienced by the object? A. 251327.4123 lb: B. 53092.9159 lb C. 16900 lbr D. 106185.8317 lb; 4. A mixture of chemicals in a variable volume batch reactor (order = 3) compresses during its chemical reaction [x = 0.90 M-?min-1). The compression coefficient (e) is equal to 1.6. If the reaction proceeds until 70% completion, determine the capacity of the reactor for an initial concentration of 0.55 mol/L fed at a rate of 12.20 L/min. A. 185.5346L В. 421.7284L C. 31.36823 L D. 12.9728 L 5. Calculate the work for the expansion of 3 moles of B,H; at 40°C from 2.74 L to 3.89 L using van der Waals equation. The correction for intermolecular forces (a) is 6.048 bar L/mol? and the adjustment factor of thevolume (b) is 0.07437 L/mol. The general equation for van der Waals is written below: n21 + a = RT A. 2352.2376J B. -2352.2376 J C. 2118.1071J D. -2118.1071 J
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