1. V E (a) Calculate is the change in PE when an electron moves through an electric field, E = 50 N/C, directed to the right, a distance of 6 m to the left. Potential Energy, APE: J (b) Is mechanical energy of the electron conserved during the motion? Yes No (c) If the electron starts from rest what is its speed, vf, after traveling 6 m? The mass of the electron is -31 me =9.1×10'kg. V = m/s
1. V E (a) Calculate is the change in PE when an electron moves through an electric field, E = 50 N/C, directed to the right, a distance of 6 m to the left. Potential Energy, APE: J (b) Is mechanical energy of the electron conserved during the motion? Yes No (c) If the electron starts from rest what is its speed, vf, after traveling 6 m? The mass of the electron is -31 me =9.1×10'kg. V = m/s
College Physics
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ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter5: Energy
Section: Chapter Questions
Problem 6WUE: A 4.00-kg crate Marling at rest slides dawn a rough 6.00-m-long ramp, inclined at 30.0 below the...
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![1.
V
E
(a) Calculate is the change in PE when an electron moves through an electric field, E = 50 N/C,
directed to the right, a distance of 6 m to the left.
Potential Energy, APE:
J
(b) Is mechanical energy of the electron conserved during the motion?
Yes v
No
(c) If the electron starts from rest what is its speed, vf, after
eling 6 m? The mass of the electron is
-31
me = 9.1x10'kg.
V; =
m/s](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff787f97c-9dc4-4f39-97ba-c4c8bbc1d69b%2F5b02ecef-1781-4228-b467-a83ffbb20a4c%2Fv3lziqa_processed.png&w=3840&q=75)
Transcribed Image Text:1.
V
E
(a) Calculate is the change in PE when an electron moves through an electric field, E = 50 N/C,
directed to the right, a distance of 6 m to the left.
Potential Energy, APE:
J
(b) Is mechanical energy of the electron conserved during the motion?
Yes v
No
(c) If the electron starts from rest what is its speed, vf, after
eling 6 m? The mass of the electron is
-31
me = 9.1x10'kg.
V; =
m/s
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Potential energy change
PE change = q(E×d)
PE change = -1.6 × 10-19 (50×6)
PE change = -4.8 × 10-17 J (a)
The mechanical energy remains conserved as there are no losses in the process (b)
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