A particle that carries a net charge of -77.8 µC is held in aconstant electric field that is uniform over the entire region.The electric field vector is oriented 55.2° clockwise from thevertical axis, as shown in the figure. If the magnitude of theelectric field is 9.82 N/C, how much work is done by theelectric field as the particle is made to move a distance ofd = 0.556 m straight up?work:What is the potential difference AV between the particle'sinitial and final positions?AV =JVdfi55.2°E

Charge q = -77.8=-77.8 =55.2The electric field E = 9.82 N/C

à particle that carries a net charge of -77.8 µC is held in a onstant electric field that is uniform over the entire region. The electric field vector is oriented 55.2° clockwise from the ertical axis, as shown in the figure. If the magnitude of the lectric field is 9.82 N/C, how much work is done by the lectric field as the particle is made to move a distance of = 0.556 m straight up? work: What is the potential difference AV between the particle's nitial and final positions? V= J V d f i 55.2°

à particle that carries a net charge of -77.8 µC is held in a onstant electric field that is uniform over the entire region. The electric field vector is oriented 55.2° clockwise from the ertical axis, as shown in the figure. If the magnitude of the lectric field is 9.82 N/C, how much work is done by the lectric field as the particle is made to move a distance of = 0.556 m straight up? work: What is the potential difference AV between the particle's nitial and final positions? V= J V d f i 55.2°

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

A particle that carries a net charge of -77.8 µC is held in a
constant electric field that is uniform over the entire region.
The electric field vector is oriented 55.2° clockwise from the
vertical axis, as shown in the figure. If the magnitude of the
electric field is 9.82 N/C, how much work is done by the
electric field as the particle is made to move a distance of
d = 0.556 m straight up?
work:
What is the potential difference AV between the particle's
initial and final positions?
AV =
J
V
d
f
i
55.2°
E

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