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Find the force vector F on an object of mass m the uniform gravitational field when it is at height z = 0. The +2 direction is up. Express vector force in terms of m, z, g. and k, where k is the unit vector in the +z direction. To create the k character: In the equation editor window, select "More", then select "Vectors", and you will find what you need. To write out a vector: for example, if the answer has both x and y components, you would answer in the format Fi + F,j F(z) = -mgk Now find the gravitational potential energy U(z) of the object when it is at an arbitrary height z. Take zero potential to be at position z=0. Keep in mind that the potential energy is a scalar, not a vector. Express U(z) in terms of m, z, and g. U(z) = mg In what direction does the object accelerate when released with initial velocity upward? downward Oupward or downward depending on the initial mass m. Oupward or downward depending on the initial velocity Oupward Now consider the analogous case of a particle with charge q placed in a uniform electric field of magnitude E, pointing downward (in the -k direction). What is F(z) in terms of q, E, z. and k? K

Find the force vector F on an object of mass m the uniform gravitational field when it is at height z = 0. The +2 direction is up. Express vector force in terms of m, z, g. and k, where k is the unit vector in the +z direction. To create the k character: In the equation editor window, select "More", then select "Vectors", and you will find what you need. To write out a vector: for example, if the answer has both x and y components, you would answer in the format Fi + F,j F(z) = -mgk Now find the gravitational potential energy U(z) of the object when it is at an arbitrary height z. Take zero potential to be at position z=0. Keep in mind that the potential energy is a scalar, not a vector. Express U(z) in terms of m, z, and g. U(z) = mg In what direction does the object accelerate when released with initial velocity upward? downward Oupward or downward depending on the initial mass m. Oupward or downward depending on the initial velocity Oupward Now consider the analogous case of a particle with charge q placed in a uniform electric field of magnitude E, pointing downward (in the -k direction). What is F(z) in terms of q, E, z. and k? K

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Find the force vector F on an object of mass m the uniform gravitational field when it is at height z = 0. The +z direction is up. Express vector force in terms of m, z. g. and k, where k is the unit vector in the +z direction. To create the k character: In the equation editor window, select "More", then select "Vectors", and you will find what you need. To write out a vector: for example, if the answer has both x and y components, you would answer in the format Fi + Fj F(z) = -mgk Now find the gravitational potential energy U(z) of the object when it is at an arbitrary height z. Take zero potential to be at position z=0. Keep in mind that the potential energy is a scalar, not a vector. Express U(z) in terms of m. z. and g. U(2)= In what direction does the object accelerate when released with initial velocity upward? downward Oupward or downward depending on the initial mass m. upward or downward depending on the initial velocity upward Now consider the analogous case of a particle with charge q placed in a uniform electric field of magnitude E, pointing downward (in the -k direction). What is F(z) in terms of q, E, z. and k ? F(z) = -qEk X
Transcribed Image Text:Find the force vector F on an object of mass m the uniform gravitational field when it is at height z = 0. The +z direction is up. Express vector force in terms of m, z. g. and k, where k is the unit vector in the +z direction. To create the k character: In the equation editor window, select "More", then select "Vectors", and you will find what you need. To write out a vector: for example, if the answer has both x and y components, you would answer in the format Fi + Fj F(z) = -mgk Now find the gravitational potential energy U(z) of the object when it is at an arbitrary height z. Take zero potential to be at position z=0. Keep in mind that the potential energy is a scalar, not a vector. Express U(z) in terms of m. z. and g. U(2)= In what direction does the object accelerate when released with initial velocity upward? downward Oupward or downward depending on the initial mass m. upward or downward depending on the initial velocity upward Now consider the analogous case of a particle with charge q placed in a uniform electric field of magnitude E, pointing downward (in the -k direction). What is F(z) in terms of q, E, z. and k ? F(z) = -qEk X
What is the potential energy U(z) of this charged particle when it is at height z? Take zero potential to be at position z=0. Express U(z) in terms of q. E, and z U(X) = GE In what direction does the charged particle accelerate when released with upward initial velocity? O upward Odownward Oupward or downward depending on the initial speed upward Oupward or downward depending on the sign of the charge q Find the electric potential (also called the voltage) V of the uniform electric field E = E k. Note that this field is not pointing in the same direction as the field in the previous section of this problem. Take zero potential to be at position z=0. Express V in terms of q. E, and z. V(z) =
Transcribed Image Text:What is the potential energy U(z) of this charged particle when it is at height z? Take zero potential to be at position z=0. Express U(z) in terms of q. E, and z U(X) = GE In what direction does the charged particle accelerate when released with upward initial velocity? O upward Odownward Oupward or downward depending on the initial speed upward Oupward or downward depending on the sign of the charge q Find the electric potential (also called the voltage) V of the uniform electric field E = E k. Note that this field is not pointing in the same direction as the field in the previous section of this problem. Take zero potential to be at position z=0. Express V in terms of q. E, and z. V(z) =
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