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Suppose an electron (q = - e = - 1.6× 10-19 C.m=9.1×10-31 kg) is accelerated from rest through a potential difference of Vab - +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U- Assuming all potential energy U is converted to kinetic energy K. K+U=0 K=-U Since K=mv and using the formula for potential energy above, we arrive at an equation for speed: v=( 1/2 Plugging in values, the value of the electron's speed is: × 107 m/s

Suppose an electron (q = - e = - 1.6× 10-19 C.m=9.1×10-31 kg) is accelerated from rest through a potential difference of Vab - +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U- Assuming all potential energy U is converted to kinetic energy K. K+U=0 K=-U Since K=mv and using the formula for potential energy above, we arrive at an equation for speed: v=( 1/2 Plugging in values, the value of the electron's speed is: × 107 m/s

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Suppose an electron (q = -e = -1.6 x 10-19C, m = 9.1 x 10-31kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures.

The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation:

U = ____________

Assuming all potential energy U is converted to kinetic energy K,

K + U = 0

K = -U

Since K = 1/2 mv2 and using the formula for potential energy above, we arrive at an equation for speed:

v = (____________)1/2

Plugging in values, the value of the electron's speed is:

v= ____________ x 107 m/s

Suppose an electron (q = - e = - 1.6× 10-19 C.m=9.1×10-31 kg) is accelerated from rest through a potential difference of Vab - +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U= Assuming all potential energy U is converted to kinetic energy K, K+U= 0 K= -U Since K =mv and using the formula for potential energy above, we arrive at an equation for speed: 1/2 Plugging in values, the value of the electron's speed is: × 107 m/s V=
Transcribed Image Text:Suppose an electron (q = - e = - 1.6× 10-19 C.m=9.1×10-31 kg) is accelerated from rest through a potential difference of Vab - +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U= Assuming all potential energy U is converted to kinetic energy K, K+U= 0 K= -U Since K =mv and using the formula for potential energy above, we arrive at an equation for speed: 1/2 Plugging in values, the value of the electron's speed is: × 107 m/s V=
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