Suppose an electron (q- -e--1.6 x 10-1º C.m=9.1× 10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U= Assuming all potential energy U is converted to kinetic energy K, K + U = 0 K = -U Since K-mv and using the formula for potential energy above, we arrive at an equation for speed: v = ( 1/2 Plugging in values, the value of the electron's speed is: V= x 10' m/s

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Chapter1: Units, Trigonometry. And Vectors
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Suppose an electron (q= -e= -1.6 x 10-19 C,m=9.1x 10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for
the final speed of the electron. Express numerical answer in two significant figures.
The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation:
U =
Assuming all potential energy U is converted to kinetic energy K,
K +U = 0
K = -U
Since K-
and using the formula for potential energy above, we arrive at an equation for speed:
v = (
51/2
Plugging in values, the value of the electron's speed is:
V=
x 107 m/s
Transcribed Image Text:Suppose an electron (q= -e= -1.6 x 10-19 C,m=9.1x 10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K +U = 0 K = -U Since K- and using the formula for potential energy above, we arrive at an equation for speed: v = ( 51/2 Plugging in values, the value of the electron's speed is: V= x 107 m/s
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