Consider two points in an electric field. The potential at point 1, V1, is 21 V. The potential at point 2, V2, is 159 V. An electron at rest at point 1 is accelerated by the electric field to point 2. Part (a)  Find the change of the electric potential energy of the electron, in electron volts (eV).  Part (b)  Find the speed of the electron at point 2, v2, in meters per second.

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A: The electric potential at x=L (L>+a) along the length of rod is found by integrating the point…

Q: At point P, what is the electric potential? What is the potential energy of an electron? At point…

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Q: E (a) Calculate is the change in PE when an electron moves through an electric field, E = 50 N/C,…

A: A. PE change = q(E×d)PE change = -1.6 × 10-19 (50×6)PE change = -4.8 × 10-17 B. The mechanical…

Q: Consider two points in an electric field. The potential at point 1, V1, is 48 V. The potential at…

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Q: When an object with an electric charge of 0.050 mC is 4.0 m away from an object with an electric…

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Q: at point where the potential is 200v. It moves through a point where the electric potential is 800v.…

A: Given value--- at first point - v1 = 4 × 109 m/s. V1 = 200 V. at second point - V2 = 600 V. We…

Q: V E (a) Calculate is the change in PE when an electron moves through an electric field, E = 60 N/C,…

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Q: Consider the following figure. 8.00 µC 2.00 μC 4.00 μC (a) Find the electric potential, taking zero…

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Q: A proton moves from a location where the electric potential is 25 V to a location where the electric…

A: Given that:- Electric potential at two locations are 25V and 10V

Q: the function: V = ax+By² describes the electric potential in a specific region in space assume…

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Q: The electric potential in a particular area varies with position as V(x) = ax2 - bx + c, where a =…

A: The electric field strength is the negative of the potential gradient.

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Q: In the science fiction story "The little prince is an android" a second journey of the character…

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Q: The two charges in the figure below are separated by d = 2.50 cm.  (Let q1 = −17.5 nC and q2 = 26.0…

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Q: à particle that carries a net charge of -77.8 µC is held in a onstant electric field that is uniform…

A: Charge q = -77.8=-77.8             =55.2The electric field E = 9.82 N/C

Q: consider a region along the x-axis where the electric potential at the origin is -160 v. Ex between…

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Q: = Two point particles have equal charge q 1100 esu and different masses, m₁ = 25 gr and m₂ = 65 gr,…

A: c. Minimum distance between the two particles At minimum distance, kinetic energy is converted into…

Q: A proton is initially at rest at a point where the potential is 473 V. Some time later the proton is…

A: from the conservation of energy The gain in kinetic energy of the proton must be equal to the change…

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Q: An electron (m = 9.1 x 10-31 kg, q = -1.6 x 10-19 C) in the picture tube of a TV is accelerated from…

A: Mass of electron (m)= 9.1*10-31 kgCharge of electron (q)= 1.6*10-19 CPotential difference= 5000 VThe…

Q: A particle that carries a net charge of -41.8 µC is held in a constant electric field that is…

A: Charge q = -41.8=-41.8             =25.2The electric field E = 7.82 N/C

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.