An electron moving parallel to the x axis has an initial speed of 3.18 x 106 m/s at the origin. Its speed is reduced to 1.80 x 105 m/s at the point x = 2.00 cm. (a) Calculate the electric potential difference between the origin and that point. Volts (b) Which point is at the higher potential? O both have the same potential O the point x = 2.00 cm O the origin Need Help? Read It Master It

College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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### Problem Description

An electron moving parallel to the x-axis has an initial speed of \(3.18 \times 10^6\) m/s at the origin. Its speed is reduced to \(1.80 \times 10^5\) m/s at the point \(x = 2.00\) cm.

#### (a) Calculate the electric potential difference between the origin and that point.
\[ \_\_\_\_\_\_\_\_\_ \text{ Volts} \]

#### (b) Which point is at the higher potential?
- ○ both have the same potential
- ○ the point \(x = 2.00 \text { cm}\)
- ○ the origin

### Need Help?
- Read It
- Master It
Transcribed Image Text:### Problem Description An electron moving parallel to the x-axis has an initial speed of \(3.18 \times 10^6\) m/s at the origin. Its speed is reduced to \(1.80 \times 10^5\) m/s at the point \(x = 2.00\) cm. #### (a) Calculate the electric potential difference between the origin and that point. \[ \_\_\_\_\_\_\_\_\_ \text{ Volts} \] #### (b) Which point is at the higher potential? - ○ both have the same potential - ○ the point \(x = 2.00 \text { cm}\) - ○ the origin ### Need Help? - Read It - Master It
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