An electron moving parallel to the x axis has an initial speed of 3.18 x 106 m/s at the origin. Its speed is reduced to 1.80 x 105 m/s at the point x = 2.00 cm. (a) Calculate the electric potential difference between the origin and that point. Volts (b) Which point is at the higher potential? O both have the same potential O the point x = 2.00 cm O the origin Need Help? Read It Master It
An electron moving parallel to the x axis has an initial speed of 3.18 x 106 m/s at the origin. Its speed is reduced to 1.80 x 105 m/s at the point x = 2.00 cm. (a) Calculate the electric potential difference between the origin and that point. Volts (b) Which point is at the higher potential? O both have the same potential O the point x = 2.00 cm O the origin Need Help? Read It Master It
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Problem Description
An electron moving parallel to the x-axis has an initial speed of \(3.18 \times 10^6\) m/s at the origin. Its speed is reduced to \(1.80 \times 10^5\) m/s at the point \(x = 2.00\) cm.
#### (a) Calculate the electric potential difference between the origin and that point.
\[ \_\_\_\_\_\_\_\_\_ \text{ Volts} \]
#### (b) Which point is at the higher potential?
- ○ both have the same potential
- ○ the point \(x = 2.00 \text { cm}\)
- ○ the origin
### Need Help?
- Read It
- Master It](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F741c2650-db79-4e2c-88df-ee07f14e26ff%2F50a9b2ff-dc34-4d44-9b7a-e06e20d83775%2Fgkejhwu_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem Description
An electron moving parallel to the x-axis has an initial speed of \(3.18 \times 10^6\) m/s at the origin. Its speed is reduced to \(1.80 \times 10^5\) m/s at the point \(x = 2.00\) cm.
#### (a) Calculate the electric potential difference between the origin and that point.
\[ \_\_\_\_\_\_\_\_\_ \text{ Volts} \]
#### (b) Which point is at the higher potential?
- ○ both have the same potential
- ○ the point \(x = 2.00 \text { cm}\)
- ○ the origin
### Need Help?
- Read It
- Master It
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