A proton with an initial speed of 850,000 m/s is brought to rest by an electric field. Part A Did the proton move into a region of higher potential or lower potential? Because the proton is a positive charge and it slows down as it travels, it must be moving from a region of higher potential to a region of lower potential. Because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of higher potential to a region of lower potential. Because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of lower potential to a region of higher potential. ● Because the proton is a positive charge and it slows down as it travels, it must be moving from a region of lower potential to a region of higher potential. Submit Previous Answers ✓ Correct Here we learn how to determine the distribution of the electric potential based on the movement of a charged particle. ▾ Part B What was the potential difference that stopped the proton? Express your answer with the appropriate units. μà AV= 6.94.10² → O V X.10 ? SWO
A proton with an initial speed of 850,000 m/s is brought to rest by an electric field. Part A Did the proton move into a region of higher potential or lower potential? Because the proton is a positive charge and it slows down as it travels, it must be moving from a region of higher potential to a region of lower potential. Because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of higher potential to a region of lower potential. Because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of lower potential to a region of higher potential. ● Because the proton is a positive charge and it slows down as it travels, it must be moving from a region of lower potential to a region of higher potential. Submit Previous Answers ✓ Correct Here we learn how to determine the distribution of the electric potential based on the movement of a charged particle. ▾ Part B What was the potential difference that stopped the proton? Express your answer with the appropriate units. μà AV= 6.94.10² → O V X.10 ? SWO
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:A proton with an initial speed of 850,000 m/s is brought to rest by an
electric field.
▾ Part A
Did the proton move into a region of higher potential or lower potential?
O Because the proton is a positive charge and it slows down as it travels, it must be moving from a region of higher potential to a region of lower potential.
O Because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of higher potential to a region of lower potential.
O Because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of lower potential to a region of higher potential.
Because the proton is a positive charge and it slows down as it travels, it must be moving from a region of lower potential to a region of higher potential.
Submit
✓ Correct
Here we learn how to determine the distribution of the electric potential based on the movement of a charged particle.
Part B
Previous Answers
What was the potential difference that stopped the proton?
Express your answer with the appropriate units.
Submit
μA
xa Xb
AV 6.94 10²
●
음
V
Po
X.10n X
Previous Answers Request Answer
?
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Transcribed Image Text:What was the initial kinetic energy of the proton, in electron volts?
Express your answer in electron volts.
IVE ΑΣΦ
K₁
wwwww ?
eV
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