I Review I Cor Part A An object with charge q = -5.00x10-9 C is placed in a region of uniform electric field and is released from rest at point A. After the charge has moved to point B, 0.500 m to the right, it has kinetic energy 5.00x10-7 J. If the electric potential at point A is +30.0 V, what is the electric potential at point B? Express your answer with the appropriate units. HA ? VB = Value Units Submit Request Answer • Part B What is the magnitude of the electric field? Express your answer with the appropriate units. Value Units E = Submit Request Answer

I Review I Cor Part A An object with charge q = -5.00x10-9 C is placed in a region of uniform electric field and is released from rest at point A. After the charge has moved to point B, 0.500 m to the right, it has kinetic energy 5.00x10-7 J. If the electric potential at point A is +30.0 V, what is the electric potential at point B? Express your answer with the appropriate units. HA ? VB = Value Units Submit Request Answer • Part B What is the magnitude of the electric field? Express your answer with the appropriate units. Value Units E = Submit Request Answer

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Part A Two electrons are in the vicinity of a proton. The potential energy of the proton is -2.40x10-25 J. What is the potential at the proton's position? Express your answer with the appropriate units. Vp = = -1.50x10-6 V Submit Previous Answers Part B Correct If one of the electrons is 1.0 cm from the proton, what is the distance of the second electron from the proton? Express your answer with the appropriate units. T2 1.06x10-3 m Submit Previous Answers VP 18.3.2 Correct Part C V = Two protons are held fixed on the x axis at x = +1 m and x = -1 m. A third proton is placed at the origin and then given a gentle nudge in the +y direction. Derive an expression for the speed of this proton as a function of its position on the y axis. Assume that it starts from rest and neglect gravity. Express your answer in terms of e, k, mp, and y. VE ΑΣΦ ?
Part A An electron starts from rest 27.5 cm from a fixed point charge with Q = -4.00 nC. How fast will the electron be moving when it is very far away? Express your answer with the appropriate units. HÀ ? Value Units V =
Part A An electron is to be accelerated from a velocity of 3.00x106 m/s to a velocity of 9.50x106 m/s. Through what potential difference must the electron pass to accomplish this? Express your answer in volts. V – V2 = V Submit Request Answer Part B Through what potential difference must the electron pass if it is to be slowed from 9.50x106 m/s to a halt? Express your answer in volts. V – V2 = V
Revie Part A A capacitor consists of two 4.1-cm-diameter circular plates separated by 1.0 mm. The plates are charged to 160 V, then the battery is removed. How much energy is stored in the capacitor? Express your answer in joules. να ΑΣφ Uc = J. %3D Submit Request Answer Part B How much work must be done to pull the plates apart to where the distance between them is 2.0 mm? Express your answer in joules. ΥΠ ΑΣΦ W = J Submit Request Answer
Figure 9 3.0 cm 14.0 cm 2.0 nC 2.0 nC 1 of 1 > Part A What is the electric potential at the point indicated with the dot in (Figure 1)? Suppose that q = -1.4 nC. Express your answer with the appropriate units. V = Submit HÅ Value Provide Feedback Request Answer Units ?
Find the force vector F on an object of mass m the uniform gravitational field when it is at height z = 0. The +z direction is up. Express vector force in terms of m, z. g. and k, where k is the unit vector in the +z direction. To create the k character: In the equation editor window, select "More", then select "Vectors", and you will find what you need. To write out a vector: for example, if the answer has both x and y components, you would answer in the format Fi + Fj F(z) = -mgk Now find the gravitational potential energy U(z) of the object when it is at an arbitrary height z. Take zero potential to be at position z=0. Keep in mind that the potential energy is a scalar, not a vector. Express U(z) in terms of m. z. and g. U(2)= In what direction does the object accelerate when released with initial velocity upward? downward Oupward or downward depending on the initial mass m. upward or downward depending on the initial velocity upward Now consider the analogous case of a particle…
A small particle has charge -4.60 µC and mass 1.70x10-4 kg. It moves from point A, where the electric potential is VA = 300 V, to point B, where the electric potential VB = 820 V is greater than the potential at point A. The electric force is the only force acting on the particle. The particle has a speed of 6.00 m/s at point A. Part A What is its speed at point B? Express your answer in meters per second. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Electric force and electric potential. m/s Part B Is it moving faster or slower at B than at A? Faster Slower 圓

Part A A 10.0 nC charge is at æ = Ocm and a -1.5 nC charge is at x = 5 cm At what point or points on the x-axis is the electric potential zero? Express your answer using two significant figures. If there is more than one answer, give each answer separated by a comma. cm Submit Request Answer Provide Feedback
Asap
Part A How far must the point charges qi = 7.10 µC and q2 = -26.1 µC be separated for the electric potential energy of the system to be -166 J ? r = cm Submit Request Answer Provide Feedback Next >
I Review | Constants Three equal 1.20 µC point charges are placed at the corners of an equilateral triangle with sides 0.700 m long. Part A What is the potential energy of the system? (Take as zero the potential energy of the three charges when they are infinitely far apart.) Express your answer with the appropriate units. μΑ U = Value J Submit Request Answer
A point charge q₁ = 4.10 nC is placed at the origin, and a second point charge q2 = -2.90 nC is placed on the x-axis at x = +20.5 cm. A third point charge q3 = 2.10 nC is to be placed on the z-axis between 9₁ and 92. (Take as zero the potential energy of the three charges when they are infinitely far apart.) Part A What is the potential energy of the system of the three charges if q3 is placed at z = +11.0 cm? Express your answer in joules. U = Submit Part B 15] ΑΣΦ Submit 1 Provide Feedback Request Answer Where should q3 be placed between 9₁ and 9₂ to make the potential energy of the system equal to zero? Express your answer in centimeters. —| ΑΣΦ ↑ P Request Answer ? J 200 ? cm