Simple problem-solving: Imagine you did a Bradford assay, and measured the absorbance of a set of protein standards and two unknowns. You repeated each measurement three times, and got the following readings in the table below. Concentration (micrograms/ml) A595 - trial 1 A595- trial 2 A595- trial 2 average A595 A595 of sample minus A595 of blank 0 1.501 1.446 1.447 1.465 0 2 1.624 1.558 1.559 1.580 0.115 5 1.731 1.749 1.712 1.731 0.266 10 1.901 1.838 1.892 1.877 0.412 15 2.161 2.108 2.228 2.166 0.701 18 2.231 2.277 2.319 2.276 0.811 unknown 1 - D1 1.717 1.713 1.644 1.691 0.226 unknown 2 - D1 1.668 1.649 1.656 1.658 0.193 concentration of unknown 1 concentration of unknown 2 Calculate the concentration of the unknowns and answer the following question: Did you need to do any manipulations before applying the standard curve to the two unknown samples? Why or why not?
Proteins
We generally tend to think of proteins only from a dietary lens, as a component of what we eat. However, they are among the most important and abundant organic macromolecules in the human body, with diverse structures and functions. Every cell contains thousands and thousands of proteins, each with specific functions. Some help in the formation of cellular membrane or walls, some help the cell to move, others act as messages or signals and flow seamlessly from one cell to another, carrying information.
Protein Expression
The method by which living organisms synthesize proteins and further modify and regulate them is called protein expression. Protein expression plays a significant role in several types of research and is highly utilized in molecular biology, biochemistry, and protein research laboratories.
Simple problem-solving: Imagine you did a Bradford assay, and measured the absorbance of a set of protein standards and two unknowns. You repeated each measurement three times, and got the following readings in the table below.
|
Concentration (micrograms/ml) |
A595 - trial 1 |
A595- trial 2 |
A595- trial 2 |
average A595 |
A595 of sample minus A595 of blank |
|
0 |
1.501 |
1.446 |
1.447 |
1.465 |
0 |
|
2 |
1.624 |
1.558 |
1.559 |
1.580 |
0.115 |
|
5 |
1.731 |
1.749 |
1.712 |
1.731 |
0.266 |
|
10 |
1.901 |
1.838 |
1.892 |
1.877 |
0.412 |
|
15 |
2.161 |
2.108 |
2.228 |
2.166 |
0.701 |
|
18 |
2.231 |
2.277 |
2.319 |
2.276 |
0.811 |
|
unknown 1 - D1 |
1.717 |
1.713 |
1.644 |
1.691 |
0.226 |
|
unknown 2 - D1 |
1.668 |
1.649 |
1.656 |
1.658 |
0.193 |
|
concentration of unknown 1 |
|
||||
|
concentration of unknown 2 |
|
Calculate the concentration of the unknowns and answer the following question:
Did you need to do any manipulations before applying the standard curve to the two unknown samples? Why or why not?
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What are the x and y values that you have input in the excel? I thought the x would be from the concentation and the y is from the A595 of sample minus A595 of blank but the linear equation that shows up in mine is different. It's y = 0.0443x + 0.0148.
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