Show that if it can be assumed that there is a pre-equilibrium involving step (1), the rate of formation of ethylene oxide is v = k,K[CH,CICH,OH][OH ], where K is the equilibrium constant for the first step and k, is the rate constant for the second step. E17E.2(b) 'The mechanism for the reaction between 2-chloroethanol, CH,CICH,OH, and hydroxide ions in aqueous solution to form ethylene oxide, (CH,CH,)0, is thought to consist of the steps (1) CH,CICH,OH+OH 2CH,CICH,O¯+H,O (2) CH,CICH,O¯ –→(CH,CH,)O+CI
Show that if it can be assumed that there is a pre-equilibrium involving step (1), the rate of formation of ethylene oxide is v = k,K[CH,CICH,OH][OH ], where K is the equilibrium constant for the first step and k, is the rate constant for the second step. E17E.2(b) 'The mechanism for the reaction between 2-chloroethanol, CH,CICH,OH, and hydroxide ions in aqueous solution to form ethylene oxide, (CH,CH,)0, is thought to consist of the steps (1) CH,CICH,OH+OH 2CH,CICH,O¯+H,O (2) CH,CICH,O¯ –→(CH,CH,)O+CI
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Show that if it can be assumed that there is a pre-equilibrium involving step
(1), the rate of formation of ethylene oxide is v = k,K[CH,CICH,OH][OH ],
where K is the equilibrium constant for the first step and k, is the rate constant
for the second step.
E17E.2(b) 'The mechanism for the reaction between 2-chloroethanol,
CH,CICH,OH, and hydroxide ions in aqueous solution to form ethylene
oxide, (CH,CH,)0, is thought to consist of the steps
(1) CH,CICH,OH+OH 2CH,CICH,O¯+H,O
(2) CH,CICH,O¯ –→(CH,CH,)O+CI](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fea860af0-a470-4c58-8105-c941838a19fa%2Ffda03c91-dae9-4ea5-97ca-8ac283a2a51a%2Fhfigc49.png&w=3840&q=75)
Transcribed Image Text:Show that if it can be assumed that there is a pre-equilibrium involving step
(1), the rate of formation of ethylene oxide is v = k,K[CH,CICH,OH][OH ],
where K is the equilibrium constant for the first step and k, is the rate constant
for the second step.
E17E.2(b) 'The mechanism for the reaction between 2-chloroethanol,
CH,CICH,OH, and hydroxide ions in aqueous solution to form ethylene
oxide, (CH,CH,)0, is thought to consist of the steps
(1) CH,CICH,OH+OH 2CH,CICH,O¯+H,O
(2) CH,CICH,O¯ –→(CH,CH,)O+CI
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