Rate Law 2 In a previous experiment, you were studying the reaction_(has nothing to do with rate law 1 above) 2A(ag) + 2B(ag) → 3C{ag) You determined the rate law to be Rate of reaction = k [A]² [B] with k at 25 °C = 0.45 units/sec I have purposely left the units off (you don't need them to answer this question). At 50 °C, you obtain the following data. [A] = 0.10 [B] = 0.10 rate of reaction = 2.25 x 103 M/sec At 5 °C, you obtain the following data. [A] = 0.10 _[B] = 0.10 rate of reaction = 1.12 x 104 M/sec Determine the rate constants k at 50 °C and 5°C and fill in the rest of the table below. Temperature Temperature k in Celsius | 1/T in Kelvin Ln k in Kelvin 25 0.45 50 AUse the following linear regression program to determine the activation energy for the reaction, remembering, the linear regression will give the equation for a straight line. Include the equation for the straight line below. y = mx + b where y = In K and x = 1/T_and m = -Eas/R

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Rate Law 2
In a previous experiment, you were studying the reaction_(has nothing to do with rate law 1 above)
2A(ag) + 2B(ag) → 3C{ag)
You determined the rate law to be
Rate of reaction = k [A]² [B] with k at 25 °C = 0.45 units/sec
I have purposely left the units off (you don't need them to answer this question).
At 50 °C, you obtain the following data.
[A] = 0.10 [B] = 0.10 rate of reaction = 2.25 x 103 M/sec
At 5 °C, you obtain the following data.
[A] = 0.10 _[B] = 0.10 rate of reaction = 1.12 x 104 M/sec
Determine the rate constants k at 50 °C and 5°C and fill in the rest of the table below.
Temperature Temperature k
in Celsius
| 1/T in Kelvin
Ln k
in Kelvin
25
0.45
50
AUse the following linear regression program to determine the activation energy for the reaction,
remembering, the linear regression will give the equation for a straight line. Include the equation for
the straight line below.
y = mx + b
where y = In K and x = 1/T_and m = -Eas/R
Transcribed Image Text:Rate Law 2 In a previous experiment, you were studying the reaction_(has nothing to do with rate law 1 above) 2A(ag) + 2B(ag) → 3C{ag) You determined the rate law to be Rate of reaction = k [A]² [B] with k at 25 °C = 0.45 units/sec I have purposely left the units off (you don't need them to answer this question). At 50 °C, you obtain the following data. [A] = 0.10 [B] = 0.10 rate of reaction = 2.25 x 103 M/sec At 5 °C, you obtain the following data. [A] = 0.10 _[B] = 0.10 rate of reaction = 1.12 x 104 M/sec Determine the rate constants k at 50 °C and 5°C and fill in the rest of the table below. Temperature Temperature k in Celsius | 1/T in Kelvin Ln k in Kelvin 25 0.45 50 AUse the following linear regression program to determine the activation energy for the reaction, remembering, the linear regression will give the equation for a straight line. Include the equation for the straight line below. y = mx + b where y = In K and x = 1/T_and m = -Eas/R
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