QUESTION Recall the reaction catalyzed by phosphoglucomutase: glucose-1-phosphate <--> glucose-6-phosphate Assume that in liver cells under fed conditions, the G1P concentration = 2.5x10-2 M, and the G6P concentration = 1x10-3 M. Using the equation AG = AGO + RTIN([product)/[reactant]), calculate AG for the reaction, given that: AGO = -7.1 kJ mol1 R = 8.315x10-3 kJ mol-1 K-1 T= 310 K (37°C) In which direction will the reaction proceed spontaneously under these conditions? O +1.2 kl mol1; reverse reaction spontaneous. O -3.5 kl mol-1; forward reaction spontaneous. O -10.7 kl mol"1; forward reaction spontaneous. O -15.4 k) mol; forward reaction spontaneous.

Biochemistry
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ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
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Chapter1: Biochemistry: An Evolving Science
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**Question 28**

Recall the reaction catalyzed by phosphoglucomutase:

\[ \text{glucose-1-phosphate} \rightleftharpoons \text{glucose-6-phosphate} \]

Assume that in liver cells under fed conditions, the G1P concentration = \(2.5 \times 10^{-2}\) M, and the G6P concentration = \(1 \times 10^{-3}\) M. Using the equation \(\Delta G = \Delta G^0 + RT \ln \left( \frac{\text{[product]}}{\text{[reactant]}} \right)\), calculate \(\Delta G\) for the reaction, given that:

\[
\Delta G^0 = -7.1 \, \text{kJ mol}^{-1}
\]
\[
R = 8.315 \times 10^{-3} \, \text{kJ mol}^{-1} \, \text{K}^{-1}
\]
\[
T = 310 \, \text{K} \, (37^\circ \text{C})
\]

In which direction will the reaction proceed spontaneously under these conditions?

- ☐ +1.2 kJ mol⁻¹; reverse reaction spontaneous.
- ☐ -3.5 kJ mol⁻¹; forward reaction spontaneous.
- ☐ -10.7 kJ mol⁻¹; forward reaction spontaneous.
- ☐ -15.4 kJ mol⁻¹; forward reaction spontaneous.
Transcribed Image Text:**Question 28** Recall the reaction catalyzed by phosphoglucomutase: \[ \text{glucose-1-phosphate} \rightleftharpoons \text{glucose-6-phosphate} \] Assume that in liver cells under fed conditions, the G1P concentration = \(2.5 \times 10^{-2}\) M, and the G6P concentration = \(1 \times 10^{-3}\) M. Using the equation \(\Delta G = \Delta G^0 + RT \ln \left( \frac{\text{[product]}}{\text{[reactant]}} \right)\), calculate \(\Delta G\) for the reaction, given that: \[ \Delta G^0 = -7.1 \, \text{kJ mol}^{-1} \] \[ R = 8.315 \times 10^{-3} \, \text{kJ mol}^{-1} \, \text{K}^{-1} \] \[ T = 310 \, \text{K} \, (37^\circ \text{C}) \] In which direction will the reaction proceed spontaneously under these conditions? - ☐ +1.2 kJ mol⁻¹; reverse reaction spontaneous. - ☐ -3.5 kJ mol⁻¹; forward reaction spontaneous. - ☐ -10.7 kJ mol⁻¹; forward reaction spontaneous. - ☐ -15.4 kJ mol⁻¹; forward reaction spontaneous.
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