Part B Calculate the nonequilibrium concentration of ethanol in yeast cells, if AG = -38.3 kJ/mol for this reaction at pH = 7.4 and 37 °C when the reactants and products are at the concentrations given above. Express your answer with the appropriate units. μA Concentration = Value Submit Request Answer Units ?
Part B Calculate the nonequilibrium concentration of ethanol in yeast cells, if AG = -38.3 kJ/mol for this reaction at pH = 7.4 and 37 °C when the reactants and products are at the concentrations given above. Express your answer with the appropriate units. μA Concentration = Value Submit Request Answer Units ?
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
Related questions
Question
3-2.23
solve part b

Transcribed Image Text:Part B
Calculate the nonequilibrium concentration of ethanol in yeast cells, if AG = −38.3 kJ/mol for this reaction at pH = 7.4 and 37 °C when the reactants and
products are at the concentrations given above.
Express your answer with the appropriate units.
HÅ
Concentration = Value
Submit
Request Answer
Units
?

Transcribed Image Text:For part B of this problem, use the following standard reduction potentials, free energies, and nonequilibrium concentrations of reactants and products:
ADP
220 μΜ
ATP = 3.10 mM
glucose = 5.10 mM
NAD+ = 350 μM
P₁ = 5.90 mM
pyruvate = 62.0 µM
NADH = 15.0 μM
Part A
>0
half reaction
<0
Submit
-
CO₂: = 15.0 torr
NAD+ + H+ + 2e¯
2pyruvate + 6H+ + 4e¯
Consider the last two steps in the alcoholic fermentation of glucose by brewer's yeast:
pyruvate + NADH + 2H+
Do you predict that ASO for this reaction is > 0 or < 0?
Previous Answers
→ NADH
→glucose
→ ethanol + NAD+ + CO₂
ATP + H₂O → ADP + P; +H+
E° (V)
-0.315
-0.590
AGO = -64.4 kJ/mol
AGO = -32.2 kJ/mol
pyruvate + NADH+ 2H+ → ethanol + NAD+ + CO₂
Correct
As written 4 reactants combine to produce 3 products (there are 2 mol H+ as written, thus there are 4 reactants). Typically, producing fewer products than
reactants would require a loss of entropy; however, in this case one of the products is a gas (and none of the reactants are gases). Gas formation is
typically associated with a significant increase in entropy. Thus, the prediction that the entropy change is > 0 is reasonable.
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