Problem 6.2. For a classical harmonic oscillator whose position and momentum are x and p define the complex amplitude a(t) = x(t) + (i/(mw))p(t) (6.38) (1/2) (a + a*) and p = -(imw/2)(a - a*). a and a* evolve accord- iwa*. Show that for a harmonic oscillator at thermal so that x = ing to a equilibrium - -iwa; à* (a²) = ((a*)²) = 0; (|a|²) = 2kBT/(mw²) Use it to show that (x(t)x(0)) = (kBT/mw²) cos(wt). (6.39)
Problem 6.2. For a classical harmonic oscillator whose position and momentum are x and p define the complex amplitude a(t) = x(t) + (i/(mw))p(t) (6.38) (1/2) (a + a*) and p = -(imw/2)(a - a*). a and a* evolve accord- iwa*. Show that for a harmonic oscillator at thermal so that x = ing to a equilibrium - -iwa; à* (a²) = ((a*)²) = 0; (|a|²) = 2kBT/(mw²) Use it to show that (x(t)x(0)) = (kBT/mw²) cos(wt). (6.39)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:Problem 6.2. For a classical harmonic oscillator whose position and momentum
are x and p define the complex amplitude
a(t) = x(t) + (i/(mw))p(t)
(6.38)
(1/2) (a + a*) and p = -(imw/2)(a - a*). a and a* evolve accord-
iwa*. Show that for a harmonic oscillator at thermal
so that x =
ing to a
equilibrium
-
-iwa; à*
(a²) = ((a*)²) = 0;
(|a|²) = 2kBT/(mw²)
Use it to show that (x(t)x(0)) = (kBT/mw²) cos(wt).
(6.39)
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