to undergo one cycle? 5-4. From Problem 5-3, we see that the period of a harmonic vibration is t = 1/v. The average of the kinetic energy over one cycle is given by 1 ==S T (K) = Interpret the result (K) = (V). mw²C² 2 Show that (K) = E/2 where E is the total energy. Show also that (V) = E/2, where the instantaneous potential energy is given by V = kC² cos² (wt + p)dt 2 - sin² (wt + p)
to undergo one cycle? 5-4. From Problem 5-3, we see that the period of a harmonic vibration is t = 1/v. The average of the kinetic energy over one cycle is given by 1 ==S T (K) = Interpret the result (K) = (V). mw²C² 2 Show that (K) = E/2 where E is the total energy. Show also that (V) = E/2, where the instantaneous potential energy is given by V = kC² cos² (wt + p)dt 2 - sin² (wt + p)
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter20: Molecular Spectroscopy And Photochemistry
Section: Chapter Questions
Problem 51AP
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only 5.4 problem, please
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