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1. 2. 3. 4. CO₂(g) + 2H2₂(g) = CH₂OH(g) ♦ C(s) + H₂O(g) = CO(g) + H₂(g) N₂(g) + 3H₂(g) = 2NH3(g) PCS(9) PC3(g) + C₂(g) Kc = 14.5 Kc =1.2 x 10-21 Ke = 1.5 x 10² Ke 3.8 x 10-² Time left 2:50:46 When the above equilibriums are listed from the one with the highest proportion of products present to the one with the smallest proportion of products, the order would be

1. 2. 3. 4. CO₂(g) + 2H2₂(g) = CH₂OH(g) ♦ C(s) + H₂O(g) = CO(g) + H₂(g) N₂(g) + 3H₂(g) = 2NH3(g) PCS(9) PC3(g) + C₂(g) Kc = 14.5 Kc =1.2 x 10-21 Ke = 1.5 x 10² Ke 3.8 x 10-² Time left 2:50:46 When the above equilibriums are listed from the one with the highest proportion of products present to the one with the smallest proportion of products, the order would be

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1. 2. 3. 4. CO₂(g) + 2H₂(g) = CH₂OH(g) ♦ C(s) + H₂O(g) = CO(g) + H₂(g) N₂(g) + 3H₂(g) = 2NH3(g) PCs(9) PC3(g) + C₂(g) K = 14.5 + K=1.2 x 10-21 Ke = 1.5 x 102 K = 3.8 x 10-² When the above equilibriums are listed from the one with the highest proportion of products present to the one with the smallest proportion of products, the order would be Time left 2:50:46 Use the following information to answer the next question. ♦
Transcribed Image Text:1. 2. 3. 4. CO₂(g) + 2H₂(g) = CH₂OH(g) ♦ C(s) + H₂O(g) = CO(g) + H₂(g) N₂(g) + 3H₂(g) = 2NH3(g) PCs(9) PC3(g) + C₂(g) K = 14.5 + K=1.2 x 10-21 Ke = 1.5 x 102 K = 3.8 x 10-² When the above equilibriums are listed from the one with the highest proportion of products present to the one with the smallest proportion of products, the order would be Time left 2:50:46 Use the following information to answer the next question. ♦
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