Why does product A form faster than product B? (three correct answers)KCI+KOHKOHКСІ+H₂OFASTERSLOWERH₂OBA In an unfavourable conformation of the starting material, A can form from a favourable transition stateBB can form from a more favourable transition state(C) The elimination reaction requires a trans-coplanar arrangement of a C-H and and a C-Cl bondDThe bulky tert-butyl group prefers an equatorial conformation

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Answered: Why does product A form faster than…

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter13: Substitution

Section: Chapter Questions

Problem 1E

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To preview image click here 3D/sahorse structure Ph Br Ph Newman projection Alkene Product For the following compound a) Draw the 3-D structure in the reactive conformation for a E2 elimination using wedge/dashed bonds to indicate stereochemistry. b) Draw a Newman projection in the reactive conformation for E2 elimination c) Give the alkene product obtained upon a E2 elimination using a non-bulky base.
The conversion of 3 alcohols into alkenes under acidic conditions involves two cationic intermediates. For each reaction, draw the complete mechanism using curved arrows.
Organic chemistry question help! Question attached b
Dehydration of 1,2,2-trimethylcyclohexanol with H2SO4 affords 1-tert-butylcyclopentene as a minor product. (a) Draw a stepwise mechanism that shows how this alkene is formed. (b) Draw other alkenes formed in this dehydration. At least one must contain a ve-membered ring.
draw the minor product
CI Br CI CI C A has the lowest boiling point least likely to undergo SN1 reaction Answer: Answer: has the best leaving group most likely to undergo SN2 reaction Answer: Answer: gives retention and inversion products has the highest boiling point when it undergoes SN1 reaction Answer: Answer: E
Which statement is correct for the following substitution reaction? of acetone + NaSH Br Select one: O the product is optically active O it is a unimolecular reaction O it is faster in aprotic solvents O the rate is unaffected by changing the concentration of NASH Oit gives a racemic mixture
Starting from the wedge-and-dash structure below (sighting down the indicated bond), rotate the back carbon to provide the structure in the conformation that will be capable of an E2 elimination. R/S stereochemistry is graded. # O H3C H Drawing > CI ||||| H Atoms, Bonds and Rings Tap a node to see s
What would be the major product of the following reaction? O CH3 || C6H5C-CHCH3 + D20 A) B) C) D) E) O CD3 C6H5C-CHCH3 O CH3 1-1 C6H5C-CDCH3 O CH3 C6D5C-CDCH3 O CD3 | | C6H5C-CDCD3 OD - C6H5CDCHCH3 CH3 OD room temp. ?
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A B Br FeBr3 1 2 0 =Li then H30* LIAIH4 then H3O* Propose reaction conditions (A) and draw the products (B, C and D) of each transformation. Curved arrow mechanisms are not required.
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