The formation constant* of [M(CN)2] is 5.30 x 1018, where M is a generic metal.A 0.150 mole quantity of M(NO3) is added to a liter of 0.790 M NaCN solution.What is the concentration of M+ ions at equilibrium?[M²] =M

Given: molM+=0.150mol;[CN−]=0.790M;V=1.00LKf(M(CN)2−)=5.30x10−18;[M+]=???MStep 1: Write the…

Answered: The formation constant* of [M(CN)2] is…

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter14: Chemical Equilibrium

Section: Chapter Questions

Problem 14.98QE

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Jj.86.

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The formation constant* of [M(CN)2] is 5.30 x 1018, where M is a generic metal. A 0.150 mole quantity of M(NO3) is added to a liter of 0.790 M NaCN solution. What is the concentration of M+ ions at equilibrium? [M²] = M