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Solved in 2 steps
- a.) Draw a eukaryotic gene with four exons (include the location of the promoter, enhancer, start and stop codon, poly-A signal sequence, 5' UTR, and 3'UTR.). b.) Draw the primary transcript. c.) Draw all of the possible fully mature mRNAs that can be produced from this locus.One of the concerns with GMO is the toxicity of product by GMO when consumed by humans. Suppose that the product is to block the 16S rRNA in the proakryotic small subunit, do you think it will have a high level of toxicity? Why? A. Yes, because the genetic code is universal. B. No, because the genetic code is NEARLY universal. C. No, because human ribosomes are different.Which one of the following isare true regarding the endogenous (made in the cell) miRNA a. They play a role in regulating the gene expression Ob. All statements are true O C. Only B&C are true d. miRNA genes encode them е. They have a loop-like structure The phrase GỌI cloned downstream of promoter in plasmid cloning means O a. GOI cloned before the promoter. O b. GOI cloned after the multiple cloning sites. O c. GOI cloned after the origin of replication. d. GOI cloned after the promoter. GỌI cloned inside the promoter sequence. е. Nucleotide misincorporation usually takes place during a. Replication b. Transformation Oc. High fidelity PCR d. Transposon insertion O e. Translation O O
- . All mutations that abolish function of the Rho termination protein in E. coli are conditional mutations;no cells with null mutations of the Rho-encoding genehave ever been isolated. What does this tell you aboutthe rho gene and its product?Transcription in prokaryotic cells O A. is initiated at a promoter and uses only one strand of DNA (the template strand) to synthesize a complementary RNA strand. B. occurs in the nucleus, whereas translation occurs in the cytoplasm. C. is terminated at a stop codon. D. does not need a promoter. O E. is initiated at a start codon with the help of initiation factors and the small subunit of the ribosome. 5Which of the following are safe havens for transposableelement insertions?a. Intronsb. Exonsc. Other transposable elementsd. a and c are both correct.
- Choose the item in column 2 that best matches each item in column 1. A. Provides information for production of protein B. Binds to promoter C. Promoter has a box A and box B consensus sequences D. Autocatalytic RNA molecules E. Associated with transcription termination F. Polymerization of ribonucleotides to form RNA molecules G. 7-methyl guanosine H. MRNA prior to processing select - 1. Core RNA polymerase select 2. rho (p) factor select 3. hnRNA select - 4. RNA select -5. RNA polymerase holoenzyme select 6. Ribozymes select - 7. 5' MRNA cap select 8. MRNAYou genetically modified a bacterium so it can only produce ribosomes from a plant.The most immediate effect on this bacterium would be;A. Nothing. It would produce proteins as normal because the genetic code isessentially universalB. It may not be able to produce proteinsC. It would not be able to transcribe mRNAD. It would not be able to remove intronsSelect the best option above and explain why you chose that answer. Yourexplanation should include a description of the role of the ribosome in the cell andhow it interacts with mRNA and tRNA. As well as explanations for why the other options are not correctHow would the artificial mRNA5′. . . GUGUGUGU . . . 3′be read according to each of the following models forthe genetic code?a. two-base, not overlappingb. two-base, overlappingc. three-base, not overlappingd. three-base, overlappinge. four-base, not overlapping
- If the sequence of an mRNA is GAGUUCACAGUAGGC, the sequence of the template strand of the corresponding gene is... which of the following answers? a. CTCAAGTGTCATCCG b. GCCTACTGTGAACTC c. 3' GAGTTCACAGTAGGC 5' d. GAGTTCACAGTAGGC e. none of the aboveThe promoter consensus sequence at the -10 BOX in the bio gene in E. coli was TAGACT; however, a transversion occurred which changed the G nucleotide to T, what outcome(s) are likely? a. transcription levels would decrease because the promoter would be weaker b. nothing would happen because the promoter would not change the mRNA sequence c. the mutation would block RNA polymerase from binding to the DNA d. transcription levels would increase because the promoter would be stronger e. the bio gene does not require a functional promoterEukaryotic MRNAS contain a poly(A) tail at the 3'-end, but the template DNA encoding the mRNA does not have poly(T)s. Identify the statements as true or false. A. The enzyme that makes polyA tail is a template-independent polymerase B. The polyA tail is added at the 3` end of MRNA C. The polyA tail is added at the 5 end of MRNA D. The polyA tail is added by DNA dependent RNA polymerase E. PolyA tail plays an essential role in transcription