Match the transfer function with correct Bode amplitude plots.✓G(s):5s+7G(s)=s+5G(s):s+ 10SSG(s) =s+ 10A.B.D.slope 20 dB/dec=slope = -20 dB/dec=slope 20 dB/dec=slope -20 dB/dec

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Answered: Match the transfer function with…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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5 Problem Match the following two frequency response diagrams: -0 0.4 |G(i w)| 0.2 10 |G(i w)| 5 Response A 2 3 4 5 6 7 8 Frequency, (rad/s) Response B 5 6 7 8 Frequency, w(rad/s) 1 2 3 4 6 6 10 10 10 to two of the following ODES 1. +x+100x = u(t) 5. +100x = u(t) 9. +100x = u(t) 3. x+x+5x= u(t) 4. x+x+x= u(t) 2. x+x+25x = u(t) : 6. x + 25xu(t) 10. +25x = u(t) 7. x+5x= u(t) 8. u(t) 11. +5x= u(t) = 12. xu(t)
Match the transfer function with correct Bode phase plots. G(s) = 5 $+7 G(s)=s+5 G(s) = s+10 S S G(s) = S+ 10 QUESTION 10 90 deg 00 0 deg -90 deg 180 deg B. D 90 deg @ 0 deg -90 deg 180 deg 90 deg @ 0 deg -90 deg 180 deg 90 deg @ 0 deg -90 deg 180 deg
Sketch frequency response of the system from part (a) in the form of Bode plot as accurately as you can.
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Match the transfer function with correct Bode phase plots. s+10 G(s)=(s+100) s+ 100 G(s)= s(s+10) G(s) = (s+10) (s+100) s(s+10) G(s) = (s+100) s(s+100) G(s)= (s+10) G(s) = (+10) (+500) S A. 180 deg- 90 deg 0 deg 90 deg 180 deg- 90 deg 00 00 0 deg C. 90 deg+ 90 deg+ 0 deg -90 deg D. 180 deg F. 90 deg 0 deg 90 deg -180 deg 90 deg 0 deg 90 deg -180 deg 90 deg 0 deg -90dex+ -180 deg 00
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AAA Show laplace transform on 1; (+) to L (y(+)) : SY(s) = x (0) Y(s) = £ [lx (+)] = 5 x(+) · est de 2 -St L [ y (^) ] = So KG) et de D 2 D D AA Y(A) → Y(s) Ŷ (+) → s Y(s) -y
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For the following open loop transfer functions, identify the correct Bode plot from the Bode plots given below: Bode Plots: 1) 3) Magnitude (dB) (Bap) eseyd 50 0 -100 -50 -150 -90 -135 -180 Magnitude (dB) -225 Phase (deg) -270 1012 -20 -40 -60 -80 -100 0 -90 -180 -270 G(s) = 10-1 Transfer function: 10 O a. 1 O b. 2 O c. 3 O d. 4 16 Bode Diagram TOP Frequency (rad/s) Bode Diagram (s+4)(s² +1.65+4) 101 Frequency (rad/s) 10 Њ 10² 10² N + Magnitude (dB) Phase (deg) Magnitude (dB) Phase (deg) 50 -50 -100 -45 -90 -135 -180 10:12 -20 -40 -60 -80 -100 -120 90 0 -90 -180 -270 1012 10 10 Bode Diagram 10² Frequency (rad/s) Bode Diagram 10² Frequency (rad/s) 10 10¹ 10² 10²
AUTO CONTROLDNO COPIED ANSWERS, SHOW FULL SOLUTION The differential equation of a DC motor can be described by the following equation Find the transfer function between the applied voltage ( Va)and the motor speed (thetadot m). What is the steady state speed of the motor after a voltage (Va = 10V) has been applied. Find the transfer function between the applied voltage (Va) and the shaft angle (thetadot m) .

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Match the transfer function with correct Bode amplitude plots. ✓ G(s): 5 s+7 G(s)=s+5 G(s): s+ 10 S S G(s) = s+ 10 A. B. D. slope 20 dB/dec = slope = -20 dB/dec = slope 20 dB/dec = slope -20 dB/dec