Homework Help is Here – Start Your Trial Now!
Engineering
Mechanical Engineering
(a) Figure Q1 shows a forced spring-mass system with damping, where mass m = 1 kg, spring constant k = 0.2 N/m, and damping coefficient c = 0.3 N-s/m. This forced spring-mass system with damping can be described by the following differential equation d2x(t) c dx(t) k dt² + + -x(t) =±F(t) m dt m m Thus, the Laplace transform function is [s² + 0.3s +0.2] X(s) = F(s)| The steady-state gain of the system is 1 [s²+0.3s+0.2] The damping ratio is 0.335 0.447 rad/s The natural frequency is

(a) Figure Q1 shows a forced spring-mass system with damping, where mass m = 1 kg, spring constant k = 0.2 N/m, and damping coefficient c = 0.3 N-s/m. This forced spring-mass system with damping can be described by the following differential equation d2x(t) c dx(t) k dt² + + -x(t) =±F(t) m dt m m Thus, the Laplace transform function is [s² + 0.3s +0.2] X(s) = F(s)| The steady-state gain of the system is 1 [s²+0.3s+0.2] The damping ratio is 0.335 0.447 rad/s The natural frequency is

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
See similar textbooks
icon
Related questions
Question
Sketch frequency response of the system from part (a) in the form of Bode plot as accurately as you can.
(a) Figure Q1 shows a forced spring-mass system with damping, where mass m = 1 kg, spring constant k = 0.2 N/m, and damping coefficient c = 0.3 N-s/m. This forced spring-mass system with damping can be described by the following differential equation d2x(t) c dx(t) k dt² + + -x(t) =±F(t) m dt m m
Transcribed Image Text:(a) Figure Q1 shows a forced spring-mass system with damping, where mass m = 1 kg, spring constant k = 0.2 N/m, and damping coefficient c = 0.3 N-s/m. This forced spring-mass system with damping can be described by the following differential equation d2x(t) c dx(t) k dt² + + -x(t) =±F(t) m dt m m
Thus, the Laplace transform function is [s² + 0.3s +0.2] X(s) = F(s)| The steady-state gain of the system is 1 [s²+0.3s+0.2] The damping ratio is 0.335 0.447 rad/s The natural frequency is
Transcribed Image Text:Thus, the Laplace transform function is [s² + 0.3s +0.2] X(s) = F(s)| The steady-state gain of the system is 1 [s²+0.3s+0.2] The damping ratio is 0.335 0.447 rad/s The natural frequency is
Expert Solution
steps

Step by step

Solved in 2 steps with 4 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Similar questions
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY
SEE MORE TEXTBOOKS