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(a) Figure Q1 shows a forced spring-mass system with damping, where mass m = 1 kg, spring constant k = 0.2 N/m, and damping coefficient c = 0.3 N-s/m. This forced spring-mass system with damping can be described by the following differential equation d2x(t) c dx(t) k dt² + + -x(t) =±F(t) m dt m m Thus, the Laplace transform function is [s² + 0.3s +0.2] X(s) = F(s)| The steady-state gain of the system is 1 [s²+0.3s+0.2] The damping ratio is 0.335 0.447 rad/s The natural frequency is

(a) Figure Q1 shows a forced spring-mass system with damping, where mass m = 1 kg, spring constant k = 0.2 N/m, and damping coefficient c = 0.3 N-s/m. This forced spring-mass system with damping can be described by the following differential equation d2x(t) c dx(t) k dt² + + -x(t) =±F(t) m dt m m Thus, the Laplace transform function is [s² + 0.3s +0.2] X(s) = F(s)| The steady-state gain of the system is 1 [s²+0.3s+0.2] The damping ratio is 0.335 0.447 rad/s The natural frequency is

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Sketch frequency response of the system from part (a) in the form of Bode plot as accurately as you can.
(a) Figure Q1 shows a forced spring-mass system with damping, where mass m = 1 kg, spring constant k = 0.2 N/m, and damping coefficient c = 0.3 N-s/m. This forced spring-mass system with damping can be described by the following differential equation d2x(t) c dx(t) k dt² + + -x(t) =±F(t) m dt m m
Transcribed Image Text:(a) Figure Q1 shows a forced spring-mass system with damping, where mass m = 1 kg, spring constant k = 0.2 N/m, and damping coefficient c = 0.3 N-s/m. This forced spring-mass system with damping can be described by the following differential equation d2x(t) c dx(t) k dt² + + -x(t) =±F(t) m dt m m
Thus, the Laplace transform function is [s² + 0.3s +0.2] X(s) = F(s)| The steady-state gain of the system is 1 [s²+0.3s+0.2] The damping ratio is 0.335 0.447 rad/s The natural frequency is
Transcribed Image Text:Thus, the Laplace transform function is [s² + 0.3s +0.2] X(s) = F(s)| The steady-state gain of the system is 1 [s²+0.3s+0.2] The damping ratio is 0.335 0.447 rad/s The natural frequency is
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