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Which of the results calculated and listed below is correct for the unknown forces shown in the FBD? P, 5 kN P₂ = 10 kN. J = 21.25 kN a2 m. a 1 m, as 0.5 m a 1 m. a; -2.5 m Angle FGH makes with the horizontal is: 26.57 degrees Angle FGB makes with the horizontal is-tan (1.5/2) P₁ KN P₂ KN am am 8 M 8m B Ea For Select one or more a. FCB=-4.00 kN Correct: this example shows the correct calculation for the force named, well done. b. Fax = 14.5 kN Correct; this example shows the correct calculation for the force named, well done. CFca-173 kN d. F = 21.3 kN Correct this example shows the correct calculation for the force named, well done. e. Fat=37.9 kN f. Fou--14.5 kN 9. Fa=13.0 kN h. Fax=-13.0 kN iFca - 43.3 kN DELL

Which of the results calculated and listed below is correct for the unknown forces shown in the FBD? P, 5 kN P₂ = 10 kN. J = 21.25 kN a2 m. a 1 m, as 0.5 m a 1 m. a; -2.5 m Angle FGH makes with the horizontal is: 26.57 degrees Angle FGB makes with the horizontal is-tan (1.5/2) P₁ KN P₂ KN am am 8 M 8m B Ea For Select one or more a. FCB=-4.00 kN Correct: this example shows the correct calculation for the force named, well done. b. Fax = 14.5 kN Correct; this example shows the correct calculation for the force named, well done. CFca-173 kN d. F = 21.3 kN Correct this example shows the correct calculation for the force named, well done. e. Fat=37.9 kN f. Fou--14.5 kN 9. Fa=13.0 kN h. Fax=-13.0 kN iFca - 43.3 kN DELL

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Please help me to find the force Fgh ?
Which of the results calculated and listed below is correct for the unknown forces shown in the FBD? P, 5 kN P₂ = 10 kN. J = 21.25 kN a2 m. a 1 m, as 0.5 m a 1 m. a; -2.5 m Angle FGH makes with the horizontal is: 26.57 degrees Angle FGB makes with the horizontal is-tan (1.5/2) P₁ KN P₂ KN am am 8 M 8m B Ea For Select one or more a. FCB=-4.00 kN Correct: this example shows the correct calculation for the force named, well done. b. Fax = 14.5 kN Correct; this example shows the correct calculation for the force named, well done. CFca-173 kN d. F = 21.3 kN Correct this example shows the correct calculation for the force named, well done. e. Fat=37.9 kN f. Fou--14.5 kN 9. Fa=13.0 kN h. Fax=-13.0 kN iFca - 43.3 kN DELL
Transcribed Image Text:Which of the results calculated and listed below is correct for the unknown forces shown in the FBD? P, 5 kN P₂ = 10 kN. J = 21.25 kN a2 m. a 1 m, as 0.5 m a 1 m. a; -2.5 m Angle FGH makes with the horizontal is: 26.57 degrees Angle FGB makes with the horizontal is-tan (1.5/2) P₁ KN P₂ KN am am 8 M 8m B Ea For Select one or more a. FCB=-4.00 kN Correct: this example shows the correct calculation for the force named, well done. b. Fax = 14.5 kN Correct; this example shows the correct calculation for the force named, well done. CFca-173 kN d. F = 21.3 kN Correct this example shows the correct calculation for the force named, well done. e. Fat=37.9 kN f. Fou--14.5 kN 9. Fa=13.0 kN h. Fax=-13.0 kN iFca - 43.3 kN DELL
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