Briefly explain the effect of the torque taken by the device that loads the motor on the variation of the torsional work and the smoothness of the motor.
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Briefly explain the effect of the torque taken by the device that loads the motor on the variation of the torsional work and the smoothness of the motor.
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- The factor of safety against slipping in the friction clutch = 1.3; coefficient of friction=0.3; working speed= 600 rpm; friction surface number= 2; If required clamping force = 2917 N, clutch outer diameter = 400 mm, clutch inner diameter = 160 mm, what is the transmitted power?If the line of best fit for your torque speed curve is described by the following equation, calculate the no-load speed of the motor. T= -0.012x+0.28The tensions in the tight and slack side of a belt drive system are 1850 N and 525 respectively. If the belt speed is 8 m/s what power in kW will be transmitted with no slippage
- Еxamples 1. When there is a reduction in amplitude over every cycle of vibration, then the body is said to have G free vibration forced vibration damped vibration none of the mentioned 2. The system of figure has degrees of freedom. Fork Joint - Two Three Spring Four Slider Five fromSolve fast pleasei need the answer quickly
- Given the information for a motor, determine its LCC in term of present worth (in $). Annual discount rate (i.e. interest rate): 10% Life time: 5 years Initial cost: $6500 Energy usage: $500/year Maintenance cost: $400/year Salvage value: $500 A 9601 B 11471 с 11068 D 12170 E 10625A device contains two bearings is to operate at 300 rev/min, 8 hours per day, 5 days per week for 5 years with a reliability of 0.99. The design load is (2006) N and an application factor of 1.2 is appropriate. Find the catalog rating C10 a)For ball bearings b) For roller bearings The Weibull parameters are x0=0.02 ,(θ-x0)=4.439 and b=1.483 Use SI units. Take the relations as C10=afFD[xD/x0+(θ-x0)(1-RD)1/b]1/a and xD=LDηD60/LR Where the subscripts D: desired R: rating f: factorQUESTION 8 Consider the equations of motion of an armature controlled DC motor given by Jw(t)+bw (t) Ki(t) = -Tfriction - Tload (t) di (t) + Ri (t) + Kw (t) = Vin (t), dt where vin(t) is the input voltage and Tload(t) is the input load torque. The outputs are the armature current i(t) and the motor speed w(t). The steady-state response of motors are specified by nominal voltage, stall torque, stall current, no load speed, and no load current. At steady-state operation, the motor equations satisfy bo) -Ki =-T -T. fric load Ri +Kov_- 55 55 The stall torque is the load torque required stead-state speed of the motor is zero. The stall current is the armature current when the motor speed is zero. The no load speed is the speed of motor when the load torque is zero. The no load current is the current when the load torque is zero. What is stall torque for this motor in N-m? Keep 3 significant figures, and do not include units. Use Scientific notation. The constants are given below. Nominal…