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Problem 2 A sector of a steel plate with endurance limit Se = 400 MPa, and ultimate strength Sut = 1000 MPa, has a stress state defining with the following cycle parameters calculated with von Mises criterion: = 130 MPa ση σα max-Mises max-Mises = = 400 MPa. Calculate the useful life in cycles according to Goodman criterion considering an equivalent cycle of completely inverted stress. Take n = 1 and work it in in sector of high cycle and finite life.

Problem 2 A sector of a steel plate with endurance limit Se = 400 MPa, and ultimate strength Sut = 1000 MPa, has a stress state defining with the following cycle parameters calculated with von Mises criterion: = 130 MPa ση σα max-Mises max-Mises = = 400 MPa. Calculate the useful life in cycles according to Goodman criterion considering an equivalent cycle of completely inverted stress. Take n = 1 and work it in in sector of high cycle and finite life.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Problem 2 A sector of a steel plate with endurance limit Se = 400 MPa, and ultimate strength Sut = 1000 MPa, has a stress state defining with the following cycle parameters calculated with von Mises criterion: = 130 MPa ση σα max-Mises max-Mises = = 400 MPa. Calculate the useful life in cycles according to Goodman criterion considering an equivalent cycle of completely inverted stress. Take n = 1 and work it in in sector of high cycle and finite life.
Transcribed Image Text:Problem 2 A sector of a steel plate with endurance limit Se = 400 MPa, and ultimate strength Sut = 1000 MPa, has a stress state defining with the following cycle parameters calculated with von Mises criterion: = 130 MPa ση σα max-Mises max-Mises = = 400 MPa. Calculate the useful life in cycles according to Goodman criterion considering an equivalent cycle of completely inverted stress. Take n = 1 and work it in in sector of high cycle and finite life.
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