Problem 2 A sector of a steel plate with endurance limit Se = 400 MPa, and ultimate strength Sut = 1000 MPa, has a stress state defining with the following cycle parameters calculated with von Mises criterion: = 130 MPa ση σα max-Mises max-Mises = = 400 MPa. Calculate the useful life in cycles according to Goodman criterion considering an equivalent cycle of completely inverted stress. Take n = 1 and work it in in sector of high cycle and finite life.
Problem 2 A sector of a steel plate with endurance limit Se = 400 MPa, and ultimate strength Sut = 1000 MPa, has a stress state defining with the following cycle parameters calculated with von Mises criterion: = 130 MPa ση σα max-Mises max-Mises = = 400 MPa. Calculate the useful life in cycles according to Goodman criterion considering an equivalent cycle of completely inverted stress. Take n = 1 and work it in in sector of high cycle and finite life.
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
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Chapter3: Torsion
Section: Chapter Questions
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
Transcribed Image Text:Problem 2
A sector of a steel plate with endurance limit Se = 400 MPa, and ultimate strength Sut = 1000 MPa,
has a stress state defining with the following cycle parameters calculated with von Mises criterion:
= 130 MPa
ση
σα
max-Mises
max-Mises
= = 400 MPa.
Calculate the useful life in cycles according to Goodman criterion considering an equivalent cycle of
completely inverted stress. Take n = 1 and work it in in sector of high cycle and finite life.
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