Please answer all parts 1. Consider an operation in which the diameter of a steel rod will be reduced from 25mm to 23mm in asingle pass. The lathe is rotating at 300 rpm. The feed is 0.4 mm/rev. The rake angle of the tool is 25degrees. Friction at the tool/chip interface is 1.5. The cutting force was measured to be 1100 N, and thechip thickness was measured to be 0.9mm. Assume ideal orthogonal cutting. Hint: You need to map thevariables to a turning operation, as shown in class.a.Sketch this operation. Show the initial and final diameters, show the tool, and note therotation speed and the direction of the feed.b. Find the shear plane angle.C.Find the stress at the shear plane (include units)d. Find the cutting speed (include units)e. Find the cutting power required to complete this operation (include units)f.Find the material removal rate (include units)g.Find the time to complete the cut if the region to be reduced in diameter is 5 cm long.

### b. Find the shear plane angle (φ)The shear plane angle can be calculated using the formula…

Answered: 1. Consider an operation in which the…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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In a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed=9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution)
In the lathe machine, the diameter of workpart 35mm is turned at 100 rpm, depth of cut 0.125 mm, length of continuous chip for one revolution of workpart = 60mm, length undeformed chip= 100.53mm, rake angle = 35°, coefficient of friction= 1.5 and resultant cutting force=215.5 N. Calculate: 1- Horizontal cutting force of the tool on the workpart and vertical cutting force required to hold the tool against the work. 2- The forces components applied against the chip by the tool. 3- Velocity of chip relative to the tool and workpart. 4- The percentage of total energy dissipated due to friction along the shear plane, and the friction at the tool-chip interface.
In a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed-9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution) L Tm- 1,= Nf N AD, vT" = C %3| AD,L Tm fv
None
Q1. Calculate the time required to machine a workpiece 170 mm long, 60 mm diameter to 165 mm long 50 mm diameter. The workpiece rotates at 440 rpm, feed is 0.3 mm/rev and maximum depth of cut is 2 mm. Assume total approach and overtravel distance as 5 mm for turning operation. Answer Q2. A gray cast iron surface 280 wide and 540mm long may be machined either on a vertical milling machine, using a 100mm - diameter face mill having eight inserted HSS teeth, or on a horizontal milling machine using an HSS slab mill with eight teeth on a 200-mm. diameter. Which machine has the faster cutting time? The values of feed per tooth and cutting speed for both processes are 0.4mm/tooth and 80m/min, respectively. The depth of cut = 3.0 mm and assume A and O equal to 5. Answer
formula and calculation
For the operation of straight turning in a lathe machine, the diameter of the workpiece is 80 mm, the length is 0.12 m, the cutting speed is 80 m / min, the feed is 0.5 mm / rev and the depth of cut is 0.002 m . Find the material removing rate and the time of machining.
Solve the math.
In an orthogonal cutting test with a bar of 75 mm diameter is reduced to 73 mm by using a HSS tool with arake angle  = 10o, following observations were made: length of the chip, lc = 69.44 mm, cutting ratio r =0.3, the horizontal component of the cutting force, FH = 1450 N, and the vertical component of the cuttingforce, FV = 850 N. The various parameters recorded in this cutting operation are: depth of cut, d = 2 mm;feed rate, f = 0.3 mm/rev, cutting speed, V = 60 m/min. Using Merchant’s theory calculate the following:1) Friction force along rake face2) Normal force acting on rake face3) Shear force along the shear plane4) Normal force acting on shear plane5) The percentage error in shear angle predicted by Merchant’s theory6) Shear velocity7) Chip velocity8) Total work done9) The shear work proportion out of the total work done10) The friction work proportion out of the total work done
Solve the math in a detailed way
In turning of stales steel alloy, 1100 mm length and 400 mm diameter, the Feed was 0.35 mm/rev, and depth of cut = 2.5 mm. The tool used in this cutting is cemented carbide tool where Taylor tool life parameters are n = 0.24 and C = 450 (tool life (min) and cutting speed (m/min). Compute the cutting speed that will allow the tool life to be 10% longer than the machining time for this part.
A 600mm*30mm flat surface of a plate is to be finish machined on a shaper .The plate has been fixed with 600 mm side along the tool travel direction. If the tool over-travel at each end of the plate is 20 mm, average cutting speed is 8 m/min, feed rate is 0.3 mm/stroke and the ratio of return time to cutting time of the tool is 1:2 Determine time required for machining?

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