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7) At the instant shown the angular velocity of link AB is 4.5 rad/sec in the CCW sense. Determine a) the angular velocity of link ED (magnitude and sense), b) the angular velocity of link BD (magnitude and sense), c) velocity vector of point D. Answers: y 250 mm D 200 mm 150 mm E WED = 8kr/s WBD = =-4.8kr/s ▼D = VB +☎BD×ĪDI B = −900i +|- 4.8k|× 250ī = -9007-1200j mm/sec

7) At the instant shown the angular velocity of link AB is 4.5 rad/sec in the CCW sense. Determine a) the angular velocity of link ED (magnitude and sense), b) the angular velocity of link BD (magnitude and sense), c) velocity vector of point D. Answers: y 250 mm D 200 mm 150 mm E WED = 8kr/s WBD = =-4.8kr/s ▼D = VB +☎BD×ĪDI B = −900i +|- 4.8k|× 250ī = -9007-1200j mm/sec

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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7) At the instant shown the angular velocity of link AB is 4.5 rad/sec in the CCW sense. Determine a) the angular velocity of link ED (magnitude and sense), b) the angular velocity of link BD (magnitude and sense), c) velocity vector of point D. Answers: y 250 mm D 200 mm 150 mm E WED = 8kr/s WBD = =-4.8kr/s ▼D = VB +☎BD×ĪDI B = −900i +|- 4.8k|× 250ī = -9007-1200j mm/sec
Transcribed Image Text:7) At the instant shown the angular velocity of link AB is 4.5 rad/sec in the CCW sense. Determine a) the angular velocity of link ED (magnitude and sense), b) the angular velocity of link BD (magnitude and sense), c) velocity vector of point D. Answers: y 250 mm D 200 mm 150 mm E WED = 8kr/s WBD = =-4.8kr/s ▼D = VB +☎BD×ĪDI B = −900i +|- 4.8k|× 250ī = -9007-1200j mm/sec
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