Kerosene at 20°C flows through the pump as shown in Figure below at 2.3 ft³/s. Head lossesbetween 1 and 2 are 8 ft, and the pump delivers 8 hp (power) to the flow. What should themercury-manometer reading h be in ft?For kerosene take p = 804 kg/m³ = 1.56 slug/ft³, or = 1.56(32.2) = 50.2 lbf/ft³. For mercury take ym = 846 lbf/ft³.x1- Select coordinates and points 1 and 22- Write down your assumptionsYmD₁ = 6 inVPump5 ft3- Apply Energy Eq. and start finding P, V, and z forpoints 1 and 2 as well as head (h) values4- Solve for unknownD₁ = 3 inh?MercuryP1V²P2+pg 2g+Z1=++Z2 +hfriction + hTurbine - hpump [pressure head]pg 2g

Step 1: Step 2: Step 3: Step 4:

Answered: Kerosene at 20°C flows through the pump…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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An industrial fan delivers 55,000 CFM of air through a discharge duct with a size of 3 ft x 4 ft where the static pressure is 6-inch water gage. At the inlet, the duct diameter is 4 ft and the static pressure is 1-inch water gage. The temperature of the air is 78 F and barometric pressure is 14 psia. (ρw = 62.2 lb/ft³). Determine: a). the total pressure in feet of air b). the static power in HP c). the fan power in HP
The water is flowing through a pipe having diameters 30 cm and 21 cm at sections land 2 respectively. The rate of flow through pipe is 40 litres/s. The section 1 is 7 m above datum and section 2 is 3 m above datum. If the pressure at section 1 is 37 N/cm? , find the following by neglecting losses: (ENTER ONLY THE VALUES BY REFERRING THE UNIT GIVEN IN BRACKETS) ) Area of cross section of section1 (unit in m?) = Area of cross section of section2 (unit in m?) = velocity at section 1 (unit in m/s) = velocity at section 2 (unit in m/s) = (ii) difference in datum head (Unit in m) = Pressure head at section 1 (Unit in m) = pressure head at section 2 (unit in m) =
U - tube is used to pressure the difference in water channel. p1= 1000 kg/m3. The orange fluid in the U - tube has a density: p2= 2000 kg/m3. The height a = 10 cm and h = 15 cm. If the pressure at point ① is 111 kPa, what is the pressure at point ② ?
Q2- Water density =1000 kg/m and viscosity is 0.001 Ns/m², is pumped between two reservoirs at 0.2m/s through a 400 m of 8 cm diameter Cast Iron pipe and several minor losses as shown in the figure. Compute the pump power required in kW. Use the last one digit of your ID number for Z1 level in meter. Screwed Z2= 50 m regular 90° elbow Sharp exit Z;= ID m Sharp entrance Half-open gate valve `bend radius Pump Open globe valve 8 cm diameter
Water flows in the horizontal pipe shown in the figure. At A the diameter is 5.00 cm and at B the diameter is 4.00 cm. The fluid in the manometer is mercury, which has a density of 13,600 kg/m3. The manometer reading h is 4.50 cm. We can treat water as an ideal fluid having a density of 1000 kg/m3. What volume of water is flowing through the pipe per second (in m3)? a) 34.2 m3/s b) 1.07 m3/s c) 5.67 x 10-2 m3/s d) 2.31 m3/s
2. Oil (sg=0.90) is flowing at 150 L/min through a turbine. The pressure before the turbine is 750 kPa and after the turbine 150 kPa with an elevation between these two points of 2.3 m [ fluid entrance is on the high side ]. If the friction loss in the system is 5.10 N.m/N find (a) the power delivered to the turbine by the fluid and (b) If the mechanical efficiency of the turbine is 80 % find the power output from the turbine.
= Water flows into a tank and out through another pipe, as shown in the figure below. The water in the tank has a surface area, Asur f 5.6 m². At the bottom of the tank there is a door inclined at an angle = 25 degrees with respect to the horizontal. The door has a length L = 1.1 m and a width w=1 m (out of the page). The flowrate into the tank is Q₁ (t) flowrate out is Qo(t) = 0.05 m³/s At time t = Asurf = 0.26 m³/s and the 0, the water has a depth ho = 2.5 m. The density of water is p = 1000 kg/m³. Ө h(t) Qout
1 m 1.4 m 1.2 ml 0.2 m A two storey building has two faucets, one in the basement and one in the first floor. The maximum water (p= 1000 kg/m³) velocity at the basement faucet, when the first floor faucet is closed, is 13 m/s. The faucet diameter is 1.5 cm. Neglect all losses. (a) How much is the maximum velocity at the first floor faucet, when the basement faucet is closed? (b) What would be a maximum height (from the basement floor) for a faucet, to still get a maximum exit velocity of 6 m/s?
Water flows inside a solid cylindrical pipe, which narrows as it goes up to a height h (see diagram below). The lower horizontal section has circular cross-sectional diameter d, whereas the upper horizontal section has diameter d/2. Let us denote A to be a point at the lower horizontal section and B to be a point at the upper horizontal section. The flow speed at A and B is uд and u, respectively. The pressure at A and B is PA and PB, respectively. РА UA Oom Ja d d/21 1 UB h (a) Assuming water to be incompressible, show that the flow speed at B is four times the flow speed at A. (b) Use Bernoulli's equation to find the drop in the water pressure from A to B. Express the result in terms of h, uд, the density of water p, and the acceleration of gravity g. (c) Above certain critical height h, vapour bubbles start to appear at the top horizontal section, which hinders water flow through the pipe. Explain why this happens.
- Find V for this mushroom cap on a pipeline. 45° 2 m r 18 m r 3 m3/s – 1 m d V
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