Please answer this question as fast as possible.Don't take longer time 3. Determine the smallest diameter pulley that 1/8 diameter steelwire can wrap around without exceeding the wires elastic limit(bending stress) of 50,000 psiPulley1/8 dia.steel wire

Step 1:Identify the given values in the problem.The given values are the diameter of the steel wire,…

Answered: 3. Determine the smallest diameter…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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What is the Share Force (in KN) at a point 0.6L (where L is the length of the plank) given that: F1 = 6.8' F2 = 14.6 F3 = 7.8 X = 4.3 y = 5.8 F1 kN F2 kN x m ym FakN B.
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1. A 300mm long composite bar is constructed by bonding an alloy steel outer sleeve of outside diameter 75 mm to a solid mild steel core of diameter 67 mm. A tensile force of 200kN was applied to the composite bar. If the modulus of elasticity for the mild steel is 208 GN/m² and that for the alloy steel is 360 GN/m². Determine the following values for the composite bar: Calculate: a) The stress in the mild steel core. a) The stress in the alloy steel sleeve. a) The extension under loading of the composite bar.
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QUESTION 4 4.2 4.1 The ratio between the outside diameter and inside diameter of a pipe is 2,5 and the length is 400 mm, when the pipe is not subjected to any load. When a tensile load of 200 kN is applied to the pipe, its length increases by 0,195 mm. The Young's modulus of elasticity for a pipe is 188 GPa. Calculate the inside diameter and outside diameter of a pipe. The following results were obtained by means of a tensile test on a carbon steel specimen, having an original cross-sectional area of 20 mm² and the gauge length is 50 mm. Elastic limit load: Elongation at the elastic limit: =0,06125 mm =4 900 N Maximum load: =7 650 N Load at fracture: =5 050 N Elongation at failure: =15,2 mm Cross-section area at failure: 7,95 mm² Calculate the following: 4.2.1 The stress at the elastic limit. 4.2.2 The maximum stress. 4.2.3 The percentage elongation. 4.2.4 The percentage reduction in area.
5. Tension test was conducted on a specimen and the following readings were recorded. Diameter = 25 mn Gauge length of extensometer = 200 mm Least count of extensometer = 0.001 mm At a load of 30 kN, extensometer reading = 60 At a load of 50 kN, extensometer reading = 100 Yield load = 160 kN Maximum load = 20s KN Diameter neck = 17 mm Final extension over 125 mm original length 150 mm Find Young's Modulus, yield stress, ultimate stress, percentage elongation and percentage reduction in area.
Please draw the free body diagram,its important.
8. A concrete wall footing with a width of 0.9 m and a depth of 0.6 m supports a centrally placed 0.6-m-thick wall. The ultimate bearing stress for the soil under the footing is 47 kN/m2. What is the height of the wall if a factor of safety of 5.0 is used? Concrete weighs 23.5 kN/m3 (assume depth of one meter) NOTE: please check options 0.6m R(m) Jestion 0.6m tely ar ate 05.16 m oogle pject) O 14.4 m MG-40 16 O5 pm ourse 1.8 m
Question 1 A tensile load of 40 kN is acting on a rod of diameter 40 mm and of length 4 m. A bore of diameter 20 mm is made centrally on the rod. To what length the rod should be bored so that the total extension will increase 30% under the same tensile load. Take E = 2 x 10$ N/mm2.
Q2. Rigid member DEF is supported by three rods, AD, BE, and CF, and the rods are of the same original dimension. Rods AD and CF are of the same material, with Young's modulus of 10.6x103 ksi, and rod BE is made of a different material, with Young's modulus of 17.0×103 ksi. Points B, E, and G are collinear, and the lengths are /₁ = 3.6 ft and /2 = 3.9 ft. Determine the force in rod CF in the unit of lb. A D 4₁ G B 1 kip -1₂- 2 C F 4
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A stepped circular bar having diameter 20 mm, 15 mm and 10 mm over axial lengths of 100 mm, 80 mm and 60 mm, respectively, is subjected to an axial tensile force of 5 kN.If E = 100×103 N/mm2and Poisson’s ratio v = 1/m = 0.32 for the material of the bar, determine a) Total change in length.b) Change in each diameter.

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3. Determine the smallest diameter pulley that 1/8 diameter steel wire can wrap around without exceeding the wires elastic limit (bending stress) of 50,000 psi Pulley 1/8 dia. steel wire