Please answer all parts 4. A turning operation is to be adopted under the following machining conditions:Cutting speed: V=80 m/minFeed rate: f=0.2 mm/revDepth of cut: w = 1.5 mmExternal workpiece diameter: D = 40 mmCalculate:a. The final workpiece diameterb. The rotational speed of the workpieceC.The tool feed rate expressed in m/mind. The material removal rate Z in mm³/mine. The specific cutting power ks assuming that the measured main force component, thecutting force Fe = 750 N.f. The power Pf in kW assuming that the measured feed force component Ff = 500 N

Given :-Cutting speed: V=80m/minFeed rate: f=0.2mm/revDepth of cut: w=1.5mmExternal workpiece…

Answered: 4. A turning operation is to be adopted…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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operation, the shear IS cIose to, In turning operation, spindle speed is set to provide a cutting speed of 2.2 m/: The feed and depth of cut are 0.32 mm and 2.1 mm, respectively. The tool rake angle is 15°. After the cut, the deformed chip thickness is measured to be 0.43 mm. Using the Orthogonal model as an approximation of turning operation, the shear strain is close to, In turning operation, spindle speed is set to provide a cutting speed of 2.4 m/
Turning Operation In a production turning operation, the foreman has decreed that a single pass must be completed on the cylindrical workpiece in 4.8 min. The piece is 400 mm long and 150 mm in diameter. Using a feed = 0.43 mm/rev and a depth of cut = 4.0 mm, what cutting speed must be used to meet this machining time requirement? Hint: Re-arrange the Tm equation to find v in m/min Tm= T.DO.L v.f 1.522
Expert Q&A Done The top surface of a rectangular workpart is machined using a peripheral milling operation. The workpart is 735 mm long by 50 mm wide by 95 mm thick. The milling cutter, which is 60 mm in diameter and has five teeth, overhangs the width of the part equally on both sides. Cutting speed = 80 m/min, chip load = 0.30 mm/tooth, and depth of cut = 7.5 mm. (a) Determine the time required to make one pass across the surface, given that the setup and machine settings provide an approach distance of 5 mm before actual cutting begins and an overtravel distance of 25 mm after 1.2 9. 20 65 73 actual cutting has finished v in seconds. (b) What is the maximum material 3.9 239 removal rate during the cut v in mm3/sec? 0.127 5
2.) On a lathe, a cylindrical work piece of 100mm diameter is being turned. The RPM is 100. The lenght of the work piece is 200mm. The feed is 0.2 mm/rev. Ignoring approach and overtravel, the machining time for one pass will be nearest to (min).
In a production turning operation, the workpart is 60 mm in diameter and 500 mm long. A feed of 0.75 mm/rev is used in the operation. If cutting speed=9 m/s, the tool must be changed every 4 workparts; But if cutting speed=5 m/s, the tool can be used to produce 50 pieces between tool changes. Determine the Taylor tool life equation for this job. (use the equations given below for solution)
A mild steel specimen of Initial diameter of 30.5 mm is turned to final diameter of 27 mm for an initial length of 153 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.4 mm/rev & Depth of cut is 0.5 mm (ii)During machining the tool's approach length is 5 mm, over run length is 2mm (iii) Time required to complete one single turning operation is 3.5 minutes (a)Find number of passes to finish the entire turning operation (b) Total time required to complete the turning operation in minutes
A slab milling operation is performed to finish the top surface of a steel workpiece 250*75 mm*mm. this will be done with a helical milling cutter with 60 mm. diameter and 8 teeth. The cutting conditions are V=30m/min, f = 0.23 mm/tooth, and t= 6 mm. Find; a) The machining time of one pass. b) The metal remove rate.
A facing operation is performed on an lathe. The diameter of the cylindrical part is 6 in and the length is 15 in The spindle rotates at 180 rpm. Use depth of cut of 0.110 in and feed of 0.008 in rev. Determine: a) The cutting speed of the tool (in/min) b) The tool feed rate (in min) c) The cutting time (sec)
thickness is HW3.A block of steel has a length L-600mm and a width W-450mm. The Machined 10mm, once by Peripheral Milling and once by planing Machine.Calculate :Machining time for each operation if you know the following For peripheral milling: cutting speed V =80 m/min, Feed f-0.15mm/rev, the cutter .1 diameter D =50 mm with five teeth and depth of cut d =3mm For planing: clearance on both sides c =25mm, cutting speed V =36.56 m/min, retum to .2 cutting ratio m =0.25, feed f=5 mm/stroke and depth of cut d =5 mm .Calculate Material removal rate in both processes .3 Solution
The end of a large tubular workpart is to be faced on a NC vertical boring mill. The part has an outside diameter of 38.0 in and an inside diameter of 24.0 in. If the facing operation is performed at a rotational speed of 40.0 rev/min, feed of 0.015 in/rev, and depth of cut of 0.180 in, determine (a) the cutting time to complete the facing operation and the cutting speeds and metal removal rates at the beginning and end of the cut.
i need the answer quickly
5.) Calculate the machining time required to reduce from 60mm diameter shaft to 50mm diameter, for a length of 1500mm with depth of cut 2mm for rough cut and 1mm for finish cut. Cutting speed and feed may be assumed as 30m/min and 0.5mm/rev respectively.

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