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Draw: The T-S diagram of the cycle. Check the critical pressure and temperature of the isobutane. Please explain the steps in the process to solve this. 1) The power plant is operating on iso-butane as a working fluid. Ob-butane mass flow rate is m = 25kg/s. For the input data see the figure. Feed water: Mass flow rate of the feed water is 200 kg/s. NOTE: - This is an ideal Rankine cycle. In this problem we assume 100% efficiency of the turbine and the pump. The processes are reversible: S1-S2 and S3=S4. Do not change the fluid type! Use international units to complete calculations The P1 pressure corresponds to the critical point Saturated vapor P1=36.29 bar. Boiler Lin Turbine Condenser Pump W 3 P2=2.26 bar 2 T6=? 6 the Cout T5=15C 5 Cooling water saturated liquid State-1 Given P₁ = 36 Sbar, h, State - 25 =710-74 kg/x9. T₁ = 140°C 15, = 24133 kg/kg.x. P₂S = 2.26 bar. , 525P 23000 3kg/kg.k. 877 kgley, ToS = 10.74°c h2s=568771919 State -2 = 2T = 085 = hi-h2 b2 = 590.07 kylky. S2=0.85= 51-52 51-525 =0 :S2 = 231725 kg/bg T2 = 23.194°c.

Draw: The T-S diagram of the cycle. Check the critical pressure and temperature of the isobutane. Please explain the steps in the process to solve this. 1) The power plant is operating on iso-butane as a working fluid. Ob-butane mass flow rate is m = 25kg/s. For the input data see the figure. Feed water: Mass flow rate of the feed water is 200 kg/s. NOTE: - This is an ideal Rankine cycle. In this problem we assume 100% efficiency of the turbine and the pump. The processes are reversible: S1-S2 and S3=S4. Do not change the fluid type! Use international units to complete calculations The P1 pressure corresponds to the critical point Saturated vapor P1=36.29 bar. Boiler Lin Turbine Condenser Pump W 3 P2=2.26 bar 2 T6=? 6 the Cout T5=15C 5 Cooling water saturated liquid State-1 Given P₁ = 36 Sbar, h, State - 25 =710-74 kg/x9. T₁ = 140°C 15, = 24133 kg/kg.x. P₂S = 2.26 bar. , 525P 23000 3kg/kg.k. 877 kgley, ToS = 10.74°c h2s=568771919 State -2 = 2T = 085 = hi-h2 b2 = 590.07 kylky. S2=0.85= 51-52 51-525 =0 :S2 = 231725 kg/bg T2 = 23.194°c.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Where do they get the 0.85 values???is it efficeincy???if so shouldi be 0.100 that would be equal to 100%?

Draw: The T-S diagram of the cycle. Check the critical pressure and temperature of the isobutane. Please explain the steps in the process to solve this. 1) The power plant is operating on iso-butane as a working fluid. Ob-butane mass flow rate is m = 25kg/s. For the input data see the figure. Feed water: Mass flow rate of the feed water is 200 kg/s. NOTE: - This is an ideal Rankine cycle. In this problem we assume 100% efficiency of the turbine and the pump. The processes are reversible: S1-S2 and S3=S4. Do not change the fluid type! Use international units to complete calculations The P1 pressure corresponds to the critical point Saturated vapor P1=36.29 bar. Boiler Lin Turbine Condenser Pump W 3 P2=2.26 bar 2 T6=? 6 the Cout T5=15C 5 Cooling water saturated liquid
Transcribed Image Text:Draw: The T-S diagram of the cycle. Check the critical pressure and temperature of the isobutane. Please explain the steps in the process to solve this. 1) The power plant is operating on iso-butane as a working fluid. Ob-butane mass flow rate is m = 25kg/s. For the input data see the figure. Feed water: Mass flow rate of the feed water is 200 kg/s. NOTE: - This is an ideal Rankine cycle. In this problem we assume 100% efficiency of the turbine and the pump. The processes are reversible: S1-S2 and S3=S4. Do not change the fluid type! Use international units to complete calculations The P1 pressure corresponds to the critical point Saturated vapor P1=36.29 bar. Boiler Lin Turbine Condenser Pump W 3 P2=2.26 bar 2 T6=? 6 the Cout T5=15C 5 Cooling water saturated liquid
State-1 Given P₁ = 36 Sbar, h, State - 25 =710-74 kg/x9. T₁ = 140°C 15, = 24133 kg/kg.x. P₂S = 2.26 bar. , 525P 23000 3kg/kg.k. 877 kgley, ToS = 10.74°c h2s=568771919 State -2 = 2T = 085 = hi-h2 b2 = 590.07 kylky. S2=0.85= 51-52 51-525 =0 :S2 = 231725 kg/bg T2 = 23.194°c.
Transcribed Image Text:State-1 Given P₁ = 36 Sbar, h, State - 25 =710-74 kg/x9. T₁ = 140°C 15, = 24133 kg/kg.x. P₂S = 2.26 bar. , 525P 23000 3kg/kg.k. 877 kgley, ToS = 10.74°c h2s=568771919 State -2 = 2T = 085 = hi-h2 b2 = 590.07 kylky. S2=0.85= 51-52 51-525 =0 :S2 = 231725 kg/bg T2 = 23.194°c.
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