Match the transfer function with correct Bode phase plots. s+10 G(s)=(s+100) s+ 100 G(s)= s(s+10) G(s) = (s+10) (s+100) s(s+10) G(s) = (s+100) s(s+100) G(s)= (s+10) G(s) = (+10) (+500) S A. 180 deg- 90 deg 0 deg 90 deg 180 deg- 90 deg 00 00 0 deg C. 90 deg+ 90 deg+ 0 deg -90 deg D. 180 deg F. 90 deg 0 deg 90 deg -180 deg 90 deg 0 deg 90 deg -180 deg 90 deg 0 deg -90dex+ -180 deg 00
Match the transfer function with correct Bode phase plots. s+10 G(s)=(s+100) s+ 100 G(s)= s(s+10) G(s) = (s+10) (s+100) s(s+10) G(s) = (s+100) s(s+100) G(s)= (s+10) G(s) = (+10) (+500) S A. 180 deg- 90 deg 0 deg 90 deg 180 deg- 90 deg 00 00 0 deg C. 90 deg+ 90 deg+ 0 deg -90 deg D. 180 deg F. 90 deg 0 deg 90 deg -180 deg 90 deg 0 deg 90 deg -180 deg 90 deg 0 deg -90dex+ -180 deg 00
Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter4: Numerical Analysis Of Heat Conduction
Section: Chapter Questions
Problem 4.6P
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Transcribed Image Text:Match the transfer function with correct Bode phase plots.
s+10
G(s)=(s+100)
s+ 100
G(s)=
s(s+10)
G(s) =
(s+10) (s+100)
s(s+10)
G(s) = (s+100)
s(s+100)
G(s)= (s+10)
G(s) =
(+10) (+500)
S
A.
180 deg-
90 deg
0 deg
90 deg
180 deg-
90 deg
00
00
0 deg
C.
90 deg+
90 deg+
0 deg
-90 deg
D.
180 deg
F.
90 deg
0 deg
90 deg
-180 deg
90 deg
0 deg
90 deg
-180 deg
90 deg
0 deg
-90dex+
-180 deg
00
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