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Find the Reversed Torsional Loading Endurance Limit S. (Note: This is the "corrected" endurance limit S not the idealized endurance limit S₁') and the 103 - Cycle Fatigue Strength for steel specimens having Ultimate Tensile Strengths of 120, 180, and 260 ksi (Hint: Remember to include the loading factor for torsional loading when calculating Sn.). 120 ksi) Ans. (Su S₁ = 34.8 ksi S103 = 86.4 ksi (Su = 180 ksi) Sn = 52.2 ksi S10³ = 129.6 ksi (Su = 260 ksi) Sn = 58 ksi S103 = 187.2 ksi

Find the Reversed Torsional Loading Endurance Limit S. (Note: This is the "corrected" endurance limit S not the idealized endurance limit S₁') and the 103 - Cycle Fatigue Strength for steel specimens having Ultimate Tensile Strengths of 120, 180, and 260 ksi (Hint: Remember to include the loading factor for torsional loading when calculating Sn.). 120 ksi) Ans. (Su S₁ = 34.8 ksi S103 = 86.4 ksi (Su = 180 ksi) Sn = 52.2 ksi S10³ = 129.6 ksi (Su = 260 ksi) Sn = 58 ksi S103 = 187.2 ksi

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Find the Reversed Torsional Loading Endurance Limit S. (Note: This is the "corrected" endurance limit S not the idealized endurance limit S₁') and the 103 - Cycle Fatigue Strength for steel specimens having Ultimate Tensile Strengths of 120, 180, and 260 ksi (Hint: Remember to include the loading factor for torsional loading when calculating Sn.). 120 ksi) Ans. (Su S₁ = 34.8 ksi S103 = 86.4 ksi (Su = 180 ksi) Sn = 52.2 ksi S10³ = 129.6 ksi (Su = 260 ksi) Sn = 58 ksi S103 = 187.2 ksi
Transcribed Image Text:Find the Reversed Torsional Loading Endurance Limit S. (Note: This is the "corrected" endurance limit S not the idealized endurance limit S₁') and the 103 - Cycle Fatigue Strength for steel specimens having Ultimate Tensile Strengths of 120, 180, and 260 ksi (Hint: Remember to include the loading factor for torsional loading when calculating Sn.). 120 ksi) Ans. (Su S₁ = 34.8 ksi S103 = 86.4 ksi (Su = 180 ksi) Sn = 52.2 ksi S10³ = 129.6 ksi (Su = 260 ksi) Sn = 58 ksi S103 = 187.2 ksi
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