1. An AISI 1018 steel has a yield strength, Sy = 295 MPa. Using the distortion energy theory for the plane stress state ox = -30 MPs, Gy = -65 MPa, and Txy = 40 MPa. 1) Determine the factor of safety. 2) Plot the safety envelope of the material. 3) Plot the load line. 4) Estimate the factor of safety by graphical method (refer to 4-1 Ductile Failure I, P10).
1. An AISI 1018 steel has a yield strength, Sy = 295 MPa. Using the distortion energy theory for the plane stress state ox = -30 MPs, Gy = -65 MPa, and Txy = 40 MPa. 1) Determine the factor of safety. 2) Plot the safety envelope of the material. 3) Plot the load line. 4) Estimate the factor of safety by graphical method (refer to 4-1 Ductile Failure I, P10).
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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![1. An AISI 1018 steel has a yield strength, Sy = 295 MPa. Using the distortion energy theory for
the plane stress state ox = -30 MPs, Oy = -65 MPa, and Txy = 40 MPa.
1) Determine the factor of safety.
2) Plot the safety envelope of the material.
3) Plot the load line.
4) Estimate the factor of safety by graphical method (refer to 4-1 Ductile Failure I, P10).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe3b63b44-9302-458a-a5f0-5e786e8527ac%2Fc4c4bb76-c7fe-478d-89a3-703f193c8af8%2Fcuzn78h_processed.png&w=3840&q=75)
Transcribed Image Text:1. An AISI 1018 steel has a yield strength, Sy = 295 MPa. Using the distortion energy theory for
the plane stress state ox = -30 MPs, Oy = -65 MPa, and Txy = 40 MPa.
1) Determine the factor of safety.
2) Plot the safety envelope of the material.
3) Plot the load line.
4) Estimate the factor of safety by graphical method (refer to 4-1 Ductile Failure I, P10).
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