i) Re-arrange the Michaelis Menten equation so it involves the ratio. Show all steps beginning Km with noting any assumptions or required conditions. d[P] = dt = K₂ [E],[S] Km+[S]' [S]O ii) Calculate the ratio for the case when the rate of product formation is 68% of Vmax and the Km substrate is in great excess. V Vmax Vmax Begin by explaining the meaning of stating simply "it's the ratio...." is not sufficient. Include in your explanation the factors that effect v and Vmax- Consider what factors make v different from or equal to Vmax. Consider what Km represents concerning processes involving ES. [S]O Km iii) Explain, in a few sentences, why the ratio determines the ratio V
i) Re-arrange the Michaelis Menten equation so it involves the ratio. Show all steps beginning Km with noting any assumptions or required conditions. d[P] = dt = K₂ [E],[S] Km+[S]' [S]O ii) Calculate the ratio for the case when the rate of product formation is 68% of Vmax and the Km substrate is in great excess. V Vmax Vmax Begin by explaining the meaning of stating simply "it's the ratio...." is not sufficient. Include in your explanation the factors that effect v and Vmax- Consider what factors make v different from or equal to Vmax. Consider what Km represents concerning processes involving ES. [S]O Km iii) Explain, in a few sentences, why the ratio determines the ratio V
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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![i) Re-arrange the Michaelis-Menten equation so it involves the ratio \(\frac{[S]_0}{K_m}\). Show all steps beginning with \[\frac{d[P]}{dt} = \frac{k_2 [E]_0 [S]}{K_m + [S]}\], noting any assumptions or required conditions.
ii) Calculate the ratio \(\frac{[S]_0}{K_m}\) for the case when the rate of product formation is 68% of \(v_{\text{max}}\) and the substrate is in great excess.
iii) Explain, in a few sentences, why the ratio \(\frac{[S]_0}{K_m}\) determines the ratio \(\frac{v}{v_{\text{max}}}\).
- Begin by explaining the meaning of \(\frac{v}{v_{\text{max}}}\), stating simply “it’s the ratio...” is not sufficient.
- Include in your explanation the factors that affect \(v\) and \(v_{\text{max}}\).
- Consider what factors make \(v\) different from or equal to \(v_{\text{max}}\).
- Consider what \(K_m\) represents concerning processes involving ES.
iv) Calculate \(K_M\) at 310K given the following rate constant information:
- \(k_1 = 17 \, \text{s}^{-1} \text{M}^{-1}\) at 300K with \(A = 7300 \, \text{s}^{-1} \text{M}^{-1}\)
- \(k_{-1} = 6 \, \text{s}^{-1}\) at 300K with \(A = 14500 \, \text{s}^{-1}\)
- \(k_2 = 31 \, \text{s}^{-1}\) at 300K with \(A = 600 \, \text{s}^{-1}\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F424482ac-ef50-4214-a1e3-aaaeb325792a%2Ffbf398cd-cdc1-42fa-b4ab-f4fa1d8f2bf5%2Fyud82r_processed.png&w=3840&q=75)
Transcribed Image Text:i) Re-arrange the Michaelis-Menten equation so it involves the ratio \(\frac{[S]_0}{K_m}\). Show all steps beginning with \[\frac{d[P]}{dt} = \frac{k_2 [E]_0 [S]}{K_m + [S]}\], noting any assumptions or required conditions.
ii) Calculate the ratio \(\frac{[S]_0}{K_m}\) for the case when the rate of product formation is 68% of \(v_{\text{max}}\) and the substrate is in great excess.
iii) Explain, in a few sentences, why the ratio \(\frac{[S]_0}{K_m}\) determines the ratio \(\frac{v}{v_{\text{max}}}\).
- Begin by explaining the meaning of \(\frac{v}{v_{\text{max}}}\), stating simply “it’s the ratio...” is not sufficient.
- Include in your explanation the factors that affect \(v\) and \(v_{\text{max}}\).
- Consider what factors make \(v\) different from or equal to \(v_{\text{max}}\).
- Consider what \(K_m\) represents concerning processes involving ES.
iv) Calculate \(K_M\) at 310K given the following rate constant information:
- \(k_1 = 17 \, \text{s}^{-1} \text{M}^{-1}\) at 300K with \(A = 7300 \, \text{s}^{-1} \text{M}^{-1}\)
- \(k_{-1} = 6 \, \text{s}^{-1}\) at 300K with \(A = 14500 \, \text{s}^{-1}\)
- \(k_2 = 31 \, \text{s}^{-1}\) at 300K with \(A = 600 \, \text{s}^{-1}\)
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