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how do you divide the rate expression for Trial 2 by that for Trial 1 and simplify? How do you solve for a?

how do you divide the rate expression for Trial 2 by that for Trial 1 and simplify? How do you solve for a?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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how do you divide the rate expression for Trial 2 by that for Trial 1 and simplify? How do you solve for a?

Write the rate laws for both Trials 1 and 2 below making sure to include the rates and concentrations of each reactant that you calculated in the table above. Don't forget the exponents a, b, and c, since you will be solving for those using this data. 125 ve For Trial 2_0.0059 = K (0,0024)' (0.020)² (0.0060) VIsmaking For Trial 10.00317 = K (0.002)' (0,020)² (0.0060)' 4-1 met he
Transcribed Image Text:Write the rate laws for both Trials 1 and 2 below making sure to include the rates and concentrations of each reactant that you calculated in the table above. Don't forget the exponents a, b, and c, since you will be solving for those using this data. 125 ve For Trial 2_0.0059 = K (0,0024)' (0.020)² (0.0060) VIsmaking For Trial 10.00317 = K (0.002)' (0,020)² (0.0060)' 4-1 met he
Trial 1 12 13 14 time (s) 250 135 60 120 Rate 0.00317 0.0059 0.013 0.00608 [BrO3-] (M) [H+] (M) 0.0012 0.020 0.0024 0.0012 0.0012 0.020 0.040 0.020 [1-] (M) 0.0060 0.0060 0.0060 0.012
Transcribed Image Text:Trial 1 12 13 14 time (s) 250 135 60 120 Rate 0.00317 0.0059 0.013 0.00608 [BrO3-] (M) [H+] (M) 0.0012 0.020 0.0024 0.0012 0.0012 0.020 0.040 0.020 [1-] (M) 0.0060 0.0060 0.0060 0.012
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